cocos2dx + android点击返回键两下退出游戏实现
发布时间:2020-12-14 21:16:59 所属栏目:百科 来源:网络整理
导读:1,修改 org/cocos2dx/lib/Cocos2dxGLSurfaceView.java下面 @Overridepublic boolean onKeyDown(final int pKeyCode,final KeyEvent pKeyEvent) { switch (pKeyCode) { case KeyEvent.KEYCODE_BACK: case KeyEvent.KEYCODE_MENU: this.queueEvent(new Runnab
1,修改org/cocos2dx/lib/Cocos2dxGLSurfaceView.java下面 @Override public boolean onKeyDown(final int pKeyCode,final KeyEvent pKeyEvent) { switch (pKeyCode) { case KeyEvent.KEYCODE_BACK: case KeyEvent.KEYCODE_MENU: this.queueEvent(new Runnable() { @Override public void run() { Cocos2dxGLSurfaceView.this.mCocos2dxRenderer.handleKeyDown(pKeyCode); } }); return true; default: return super.onKeyDown(pKeyCode,pKeyEvent); } }为: @Override public boolean onKeyDown(final int pKeyCode,final KeyEvent pKeyEvent) { switch (pKeyCode) { case KeyEvent.KEYCODE_BACK: return false; case KeyEvent.KEYCODE_MENU: this.queueEvent(new Runnable() { @Override public void run() { Cocos2dxGLSurfaceView.this.mCocos2dxRenderer.handleKeyDown(pKeyCode); } }); return true; default: return super.onKeyDown(pKeyCode,pKeyEvent); } }按键KeyEvent.KEYCODE_BACK被监听了,只要在这里不作处理即可(return false) 2,添加代码
// private long exitTime = 0; @Override public boolean onKeyDown(int keyCode,KeyEvent event){ Log.e("<<<onKeyDown","<<<onKeyDown"); if(keyCode == KeyEvent.KEYCODE_BACK && event.getAction() == KeyEvent.ACTION_DOWN){ if(System.currentTimeMillis() - exitTime > 2000){ Toast.makeText(getApplicationContext(),"再按一次退出程序",Toast.LENGTH_SHORT).show(); exitTime = System.currentTimeMillis(); }else{ finish(); System.exit(0); } return true; } return super.onKeyDown(keyCode,event); } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |