iphone – 表脚中的UIButton没有响应

发布时间：2020-12-14 18:05:22 所属栏目：百科来源：网络整理

导读：对于自定义表格页脚,我使用以下代码 - (UIView *)tableView:(UITableView *)tableView viewForFooterInSection:(NSInteger)section { if(editmode) { if(footerView == nil) { //allocate the view if it doesn't exist yet footerView = [[UIView alloc] in

对于自定义表格页脚,我使用以下代码

- (UIView *)tableView:(UITableView *)tableView viewForFooterInSection:(NSInteger)section {
    if(editmode) {
    if(footerView == nil) {
        //allocate the view if it doesn't exist yet
        footerView  = [[UIView alloc] init];

        //we would like to show a gloosy red button,so get the image first
        UIImage *image = [[UIImage imageNamed:@"button_green.png"] stretchableImageWithLeftCapWidth:8 topCapHeight:8];

        //create the button
        UIButton *button = [UIButton buttonWithType:UIButtonTypeRoundedRect];
        [button setBackgroundImage:image forState:UIControlStateNormal];

        //the button should be as big as a table view cell
        [button setFrame:CGRectMake(10,3,300,44)];

        //set title,font size and font color
        [button setTitle:@"Photo" forState:UIControlStateNormal];
        [button.titleLabel setFont:[UIFont boldSystemFontOfSize:20]];
        [button setTitleColor:[UIColor whiteColor] forState:UIControlStateNormal];

        //set action of the button
        [button addTarget:self action:@selector(selectExistingPicture) forControlEvents:UIControlEventTouchUpInside];

        //add the button to the view
        [footerView addSubview:button];
        UIButton *button2 = [UIButton buttonWithType:UIButtonTypeRoundedRect];
        image = [[UIImage imageNamed:@"button_grey_dark.png"] stretchableImageWithLeftCapWidth:8 topCapHeight:8];
        [button2 setBackgroundImage:image forState:UIControlStateNormal];

        //the button should be as big as a table view cell
        [button2 setFrame:CGRectMake(10,50,font size and font color
        [button2 setTitle:@"Note" forState:UIControlStateNormal];
        [button2.titleLabel setFont:[UIFont boldSystemFontOfSize:20]];
        [button2 setTitleColor:[UIColor whiteColor] forState:UIControlStateNormal];

        //set action of the button
        [button2 addTarget:self action:@selector(mkFolder) forControlEvents:UIControlEventTouchUpInside];

        //add the button to the view
        [footerView addSubview:button2];

        //      [button setupAsRedButton];
    }

    //return the view for the footer
    return footerView;
    } 
    return nil;
}

使用它,第一个按钮响应完美,但第二个按钮不记录任何事件.即使该函数不存在,也不会生成空函数错误.关于UITouchUpInside未被识别的任何想法？

解决方法

卫生署！

在这段代码的正下方,我有

// specify the height of your footer section
- (CGFloat)tableView:(UITableView *)tableView
heightForFooterInSection:(NSInteger)section {
    //differ between your sections or if you
    //have only on section return a static value
    return 50;
}

这使得UIView忽略了50像素以下的任何东西.将它改为100,我很好.

（编辑：李大同）

【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容!