六种语言实现输出乘法口诀表
发布时间:2020-12-14 07:04:58 所属栏目:百科 来源:网络整理
导读:六种语言实现输出乘法口诀表 Objective-c #import Foundation/Foundation.h int main( int argc,const char * argv[]) { @autoreleasepool { for ( int a= 1 ; a= 9 ; a++) { for ( int b= 1 ; b=a; b++) { printf ( " %dx %d = %d t" ,b,a,a *b ); } print
六种语言实现输出乘法口诀表
#import <Foundation/Foundation.h>
int main(int argc,const char * argv[]) {
@autoreleasepool {
for (int a=1; a<=9; a++) {
for (int b=1; b<=a; b++) {
printf("%dx%d = %dt",b,a,a*b);
}
printf("n");
}
}
return 1;
}
#include <stdio.h>
int main(void){
int a,b;
for (a=1; a<=9; a++) {
for (b=1; b<=a; b++) {
printf("%dx%d = %dt",a*b);
}
printf("n");
}
return 0;
}
package hello;
public class main {
public static void main(String args[]){
for (int a=1; a<=9; a++) {
for (int b=1; b<=a; b++) {
System.out.printf("%d x %d = %dt",a*b);
}
System.out.printf("n");
}
}
}
for (var a = 1; a <10 ;a++){
for (var b =1;b< a+1;b++){
document.write(b+"×"+a+"="+(b*a)+" ")
}
document.write("<br>")
}
import Cocoa
for a in 1...9{
for b in 1...a{
print("(b)x(a) = (b*a)",terminator:"t")
}
print("")
}
for a in range(1,10):
for b in range(1,a+1):
print(b,"x",a,"=",a*b,end="t")
print("")
可以看出 不同语言又不同的写法,从上到下,代码越来越少,越来越简洁,也能够看出这些语言的各自的一些特点。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |