swift – 使用ObjectIdentifier()和’===’运算符之间的区别
假设我在Swift中实现了一个根类,我声明它采用了Equatable协议(我希望能够判断我的类型的数组是否包含给定的实例).
有什么区别 – 在这种特定情况下 – 在实现协议的required ==运算符之间有什么区别: public static func ==(lhs: MyClass,rhs: MyClass) -> Bool { return ObjectIdentifier(lhs) == ObjectIdentifier(rhs) } ……而不是这样做: public static func ==(lhs: MyClass,rhs: MyClass) -> Bool { return (lhs === rhs) } 作为参考,这是文档中关于ObjectIdentifier()的内容:
…这就是The Swift Programming Language (Swift 3)的“基本运算符”部分对===运算符的说法:
类实例没有区别,请参阅以下内容
comments in ObjectIdentifier.swift: /// Creates an instance that uniquely identifies the given class instance. /// /// The following example creates an example class `A` and compares instances /// of the class using their object identifiers and the identical-to /// operator (`===`): /// /// class IntegerRef { /// let value: Int /// init(_ value: Int) { /// self.value = value /// } /// } /// /// let x = IntegerRef(10) /// let y = x /// /// print(ObjectIdentifier(x) == ObjectIdentifier(y)) /// // Prints "true" /// print(x === y) /// // Prints "true" /// /// let z = IntegerRef(10) /// print(ObjectIdentifier(x) == ObjectIdentifier(z)) /// // Prints "false" /// print(x === z) /// // Prints "false" /// 从中也可以看出这一点 public static func == (x: ObjectIdentifier,y: ObjectIdentifier) -> Bool { return Bool(Builtin.cmp_eq_RawPointer(x._value,y._value)) } 这是the public func === (lhs: AnyObject?,rhs: AnyObject?) -> Bool { switch (lhs,rhs) { case let (l?,r?): return Bool(Builtin.cmp_eq_RawPointer( Builtin.bridgeToRawPointer(Builtin.castToUnknownObject(l)),Builtin.bridgeToRawPointer(Builtin.castToUnknownObject(r)) )) case (nil,nil): return true default: return false } } ObjectIdentifier符合Hashable,因此如果您想为您的类实现该协议,它会很有用: extension MyClass: Hashable { var hashValue: Int { return ObjectIdentifier(self).hashValue } } 还可以为元类型创建对象标识符(例如,ObjectIdentifier(Float.self)),其中未定义===. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |