如何将Swift结构作为参数传递给Objective-C方法

发布时间：2020-12-14 05:33:13 所属栏目：百科来源：网络整理

导读：我有一个Objective-C方法接受id类型的参数,我想传递一个 Swift结构. ObjcClass.m文件： @implementation ObjcClass+ (void)addListener:(id)listener { // Do something with listener} DemoStruct.swift文件： struct DemoStruct { func registerAsListener

我有一个Objective-C方法接受id类型的参数,我想传递一个 Swift结构.

ObjcClass.m文件：

@implementation ObjcClass
+ (void)addListener:(id)listener {
    // Do something with listener
}

DemoStruct.swift文件：

struct DemoStruct {
    func registerAsListener() {
        ObjcClass.addListener(self) // Can't find a way to do this
    }
}

我得到的编译错误消息：

Type ‘DemoStruct’ does not conform to protocol ‘AnyObject’

所以我的问题是,如何使Objective-C方法接受Any而不是AnyObject并且有这样的事情？

你不能这样做.

从Objective-C无法访问Swift结构.这在Apple的“使用Swift With Cocoa和Objective-C”一书中有所说明：

You’ll have access to anything within a class or protocol that’s marked with the @objc attribute as long as it’s compatible with Objective-C. This excludes Swift-only features such as those listed here:

Generics

Tuples

Enumerations defined in Swift

Structures defined in Swift

Top-level functions defined in Swift

Global variables defined in Swift

Typealiases defined in Swift

Swift-style variadics

Nested types

Curried functions

摘录自：Apple Inc.“将Swift与Cocoa和Objective-C结合使用.”iBooks. https://itun.es/gb/1u3-0.l

（编辑：李大同）

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