正则表达式 – 删除两个括号之间的所有文本

发布时间：2020-12-13 22:55:18 所属栏目：百科来源：网络整理

导读：假设我有这样的文字, text-c("[McCain]: We need tax policies that respect the wage earners and job creators. [Obama]: It's harder to save. It's harder to retire. [McCain]: The biggest problem with American healthcare system is that it costs

假设我有这样的文字,

text<-c("[McCain]: We need tax policies that respect the wage earners and job creators. [Obama]: It's harder to save. It's harder to retire. [McCain]: The biggest problem with American healthcare system is that it costs too much. [Obama]: We will have a healthcare system,not a disease-care system. We have the chance to solve problems that we've been talking about... [Text on screen]: Senators McCain and Obama are talking about your healthcare and financial security. We need more than talk. [Obama]: ...year after year after year after year. [Announcer]: Call and make sure their talk turns into real solutions. AARP is responsible for the content of this advertising.")

我想删除(编辑：摆脱)[和](和括号本身)之间的所有文本.最好的方式是做什么？这是我使用正则表达式和stingr包的微弱尝试：

str_extract(text,"[[a-z]*]")

感谢任何帮助！

有了这个：

gsub("[[^]]*]","",subject,perl=TRUE);

正则表达式是什么意思

[                       # '['
  [^]]*                   # any character except: ']' (0 or more
                           # times (matching the most amount possible))
  ]                       # ']'

（编辑：李大同）

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