POSTGRESQL交叉表的实现
发布时间:2020-12-13 17:24:24 所属栏目:百科 来源:网络整理
导读:这里我来演示下在POSTGRESQL里面如何实现交叉表的展示,至于什么是交叉表,我就不多说了,度娘去哦。 原始表数据如下: t_girl=# select * from score; name | subject | score -------+---------+------- Lucy | English | 100 Lucy | Physics | 90 Lucy | M
这里我来演示下在POSTGRESQL里面如何实现交叉表的展示,至于什么是交叉表,我就不多说了,度娘去哦。
原始表数据如下: t_girl=# select * from score; name | subject | score -------+---------+------- Lucy | English | 100 Lucy | Physics | 90 Lucy | Math | 85 Lily | English | 95 Lily | Physics | 81 Lily | Math | 84 David | English | 100 David | Physics | 86 David | Math | 89 Simon | English | 90 Simon | Physics | 76 Simon | Math | 79 (12 rows) Time: 2.066 ms 想要实现以下的结果: name | English | Physics | Math -------+---------+---------+------ Simon | 90 | 76 | 79 Lucy | 100 | 90 | 85 Lily | 95 | 81 | 84 David | 100 | 86 | 89 大致有以下几种方法: 1、用标准SQL展现出来 t_girl=# select name,t_girl-# sum(case when subject = 'English' then score else 0 end) as "English",t_girl-# sum(case when subject = 'Physics' then score else 0 end) as "Physics",t_girl-# sum(case when subject = 'Math' then score else 0 end) as "Math" t_girl-# from score t_girl-# group by name order by name desc; name | English | Physics | Math -------+---------+---------+------ Simon | 90 | 76 | 79 Lucy | 100 | 90 | 85 Lily | 95 | 81 | 84 David | 100 | 86 | 89 (4 rows) Time: 1.123 ms 2、用PostgreSQL 提供的第三方扩展 tablefunc 带来的函数实现 以下函数crosstab 里面的SQL必须有三个字段,name,分类以及分类值来作为起始参数,必须以name,分类值作为输出参数。 t_girl=# SELECT * FROM crosstab('select name,subject,score from score order by name desc',$$values ('English'::text),('Physics'::text),('Math'::text)$$) AS score(name text,English int,Physics int,Math int); name | english | physics | math -------+---------+---------+------ Simon | 90 | 76 | 79 Lucy | 100 | 90 | 85 Lily | 95 | 81 | 84 David | 100 | 86 | 89 (4 rows) Time: 2.059 ms 3、用PostgreSQL 自身的聚合函数实现 t_girl=# select name,split_part(split_part(tmp,',1),':',2) as "English",t_girl-# split_part(split_part(tmp,2),2) as "Physics",3),2) as "Math" t_girl-# from t_girl-# ( t_girl(# select name,string_agg(subject||':'||score,') as tmp from score group by name order by name desc t_girl(# ) as T; name | English | Physics | Math -------+---------+---------+------ Simon | 90 | 76 | 79 Lucy | 100 | 90 | 85 Lily | 95 | 81 | 84 David | 100 | 86 | 89 (4 rows) Time: 2.396 ms 4、 存储函数实现 create or replace function func_ytt_crosstab_py () returns setof ytt_crosstab as $ytt$ for row in plpy.cursor("select name,') as tmp from score group by name order by name desc"): a = row['tmp'].split(',') yield (row['name'],a[0].split(':')[1],a[1].split(':')[1],a[2].split(':')[1]) $ytt$ language plpythonu; t_girl=# select name,english,physics,math from func_ytt_crosstab_py(); name | english | physics | math -------+---------+---------+------ Simon | 90 | 76 | 79 Lucy | 100 | 90 | 85 Lily | 95 | 81 | 84 David | 100 | 86 | 89 (4 rows) Time: 2.687 ms 5、 用PLPGSQL来实现 t_girl=# create type ytt_crosstab as (name text,English text,Physics text,Math text); CREATE TYPE Time: 22.518 ms create or replace function func_ytt_crosstab () returns setof ytt_crosstab as $ytt$ declare v_name text := ''; v_english text := ''; v_physics text := ''; v_math text := ''; v_tmp_result text := ''; declare cs1 cursor for select name,') from score group by name order by name desc; begin open cs1; loop fetch cs1 into v_name,v_tmp_result; exit when not found; v_english = split_part(split_part(v_tmp_result,2); v_physics = split_part(split_part(v_tmp_result,2); v_math = split_part(split_part(v_tmp_result,2); return query select v_name,v_english,v_physics,v_math; end loop; end; $ytt$ language plpgsql; t_girl=# select name,English,Physics,Math from func_ytt_crosstab(); name | english | physics | math -------+---------+---------+------ Simon | 90 | 76 | 79 Lucy | 100 | 90 | 85 Lily | 95 | 81 | 84 David | 100 | 86 | 89 (4 rows) Time: 2.127 ms (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |