在Postgresql上配对顺序事件
发布时间:2020-12-13 16:09:17 所属栏目:百科 来源:网络整理
导读:我们正在记录用户在桌面上的iPad应用程序上执行的主要操作流程.每个流都有一个开始(标记为已启动)和一个标记为已取消或已完成的结束,并且不应存在任何重叠事件. 为用户启动,取消或完成的一组流程如下所示: user_id timestamp event_text event_numinfo@cafe
我们正在记录用户在桌面上的iPad应用程序上执行的主要操作流程.每个流都有一个开始(标记为已启动)和一个标记为已取消或已完成的结束,并且不应存在任何重叠事件.
为用户启动,取消或完成的一组流程如下所示: user_id timestamp event_text event_num info@cafe-test.de 2016-10-30 00:08:00.966+00 Flow Started 0 info@cafe-test.de 2016-10-30 00:08:15.58+00 Flow Cancelled 2 info@cafe-test.de 2016-10-30 00:08:15.581+00 Flow Started 0 info@cafe-test.de 2016-10-30 00:34:44.134+00 Flow Finished 1 info@cafe-test.de 2016-10-30 00:42:26.102+00 Flow Started 0 info@cafe-test.de 2016-10-30 00:42:49.276+00 Flow Cancelled 2 info@cafe-test.de 2016-10-30 00:42:49.277+00 Flow Started 0 info@cafe-test.de 2016-10-30 00:59:47.337+00 Flow Cancelled 2 info@cafe-test.de 2016-10-30 00:59:47.337+00 Flow Started 0 info@cafe-test.de 2016-10-30 00:59:47.928+00 Flow Cancelled 2 我们想要计算取消流量和完成流量的平均持续时间.为此,我们需要将事件Started与Cancelled或Finished配对.以下代码执行此操作,但无法解决我们遇到的以下数据质量问题: >当客户想要在结束正在进行的流程(Flow1)之前启动新流程(让我们称之为Flow2)时,我们会在拍摄新流程的已启动事件时拍摄已取消的事件.所以Flow1已取消= Flow2已启动.但是,当我们使用窗口函数进行排序时,实际属于不同流的有序事件之间的超前/滞后得到匹配. WITH track_scf AS (SELECT user_id,timestamp,event_text,CASE WHEN event_text LIKE '%Started%' THEN 0 when event_text like '%Cancelled%' then 2 ELSE 1 END AS event_num FROM tracks ORDER BY 2,4 desc ) SELECT user_id,CASE WHEN event_num=0 then timestamp end as start,CASE WHEN LEAD(event_num,1) OVER (PARTITION BY user_id ORDER BY timestamp,event_num) <> 0 THEN LEAD(timestamp,event_num) END as end,event_num) <> 0 THEN LEAD(event_num,event_num) END as action FROM track_scf 我们得到这个结果: user_id start end action info@cafe-test.de 2016-10-30 00:08:00.966+00 2016-10-30 00:08:15.58+00 2 info@cafe-test.de 2016-10-30 00:08:15.581+00 2016-10-30 00:34:44.134+00 1 info@cafe-test.de 2016-10-30 00:42:26.102+00 2016-10-30 00:42:49.276+00 2 info@cafe-test.de 2016-10-30 00:42:49.277+00 NULL NULL info@cafe-test.de 2016-10-30 00:59:47.337+00 2016-10-30 00:59:47.337+00 2 info@cafe-test.de NULL 2016-10-30 00:59:47.928+00 2 但我们应该得到这个: user_id start end action info@cafe-test.de 2016-10-30 00:08:00.966+00 2016-10-30 00:08:15.58+00 2 info@cafe-test.de 2016-10-30 00:08:15.581+00 2016-10-30 00:34:44.134+00 1 info@cafe-test.de 2016-10-30 00:42:26.102+00 2016-10-30 00:42:49.276+00 2 info@cafe-test.de 2016-10-30 00:42:49.277+00 2016-10-30 00:59:47.337+00 2 info@cafe-test.de 2016-10-30 00:59:47.337+00 2016-10-30 00:59:47.928+00 2 如何更改代码以使配对正确? 解决方法select user_id,"start","end","action" from (select user_id,timestamp as "start",lead (event_num) over w as "action",lead ("timestamp") over w as "end",event_num from tracks t window w as (partition by user_id order by "timestamp",event_num desc) ) t where t.event_num = 0 ; (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |