sqlite数据库中第一条数据查不出来！

发布时间：2020-12-12 19:44:48 所属栏目：百科来源：网络整理

导读：/** * *Title:selectAllPhone *Description:查询所有的Phone对象 *@return *@see * com.sms.ntlm.dao.PhoneDao#selectAllPhone() */ @SuppressLint("SimpleDateFormat") @SuppressWarnings("deprecation") @Override public ListPhone selectAllPhone() { Cu

/**
* *Title:selectAllPhone *Description:查询所有的Phone对象 *@return *@see
* com.sms.ntlm.dao.PhoneDao#selectAllPhone()
*/
@SuppressLint("SimpleDateFormat")
@SuppressWarnings("deprecation")
@Override
public List<Phone> selectAllPhone() {
Cursor cursor=null;
List<Phone> list=new ArrayList<Phone>();
String sql="select * from "+PhoneSQLConstant.TABLE_NAME+";";
db=mOpenHelper.getWritableDatabase();
if(mOpenHelper!=null && db.isOpen()){
// cursor=db.query(PhoneSQLConstant.TABLE_NAME,null,null);
cursor=db.rawQuery(sql,null);
}
if (cursor != null) {//原因就是这个地方出错了：我在这个地方加了个if (cursor != null && cursor.moveToFirst()) {
while (cursor.moveToNext()) {
Phone phone=new Phone();

phone.setPhoneId(cursor.getInt(cursor.getColumnIndex(PhoneSQLConstant.PHONE_ID)));
phone.setPhoneNum(cursor.getString(cursor.getColumnIndex(PhoneSQLConstant.PHONE_NUM)));
phone.setPhoneDate(cursor.getString(cursor.getColumnIndex(PhoneSQLConstant.PHONE_DATE)));

list.add(phone);
}
}
this.closeCursorDB(cursor);
return list;

}

控制台输出的结果是:05-15 03:12:44.017: I/System.out(12634): testselectAllPhone.size()..............0

我在数据库中查询的结果是：

D:zzz>sqlite3 PhoneMassage.db SQLite version 3.7.11 2012-03-20 11:35:50 Enter ".help" for instructions Enter SQL statements terminated with a ";" sqlite> .table MyPhone Phone android_metadata sqlite> select * from MyPhone ...> ; 1|1234|2015-05-15 sqlite> ^C

（编辑：李大同）

【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容!