Oracle左关联可能导致分区用不上
发布时间:2020-12-12 13:54:53 所属栏目:百科 来源:网络整理
导读:今天有一条SQL没有使用上分区,导致了严重的性能问题,下面来模拟一下: drop table test1; drop table test2; create table test1 ( ID VARCHAR2(32), name VARCHAR2(50), BUREAU_CODE VARCHAR2(4) ) partition by list (BUREAU_CODE) ( partition p1 value
今天有一条SQL没有使用上分区,导致了严重的性能问题,下面来模拟一下: drop table test1; drop table test2;create table test1 ( ID VARCHAR2(32), name VARCHAR2(50), BUREAU_CODE VARCHAR2(4) ) partition by list (BUREAU_CODE) ( partition p1 values ('0302'), partition p2 values ('0303'), partition p3 values ('0304') ); insert into test1 values(1,'a','0302'); insert into test1 values(2,'b','0302'); insert into test1 values(3,'c','0303'); insert into test1 values(4,'d','0303'); insert into test1 values(5,'e','0304'); insert into test1 values(6,'f','0304'); commit; create table test2 ( ID VARCHAR2(32), partition p3 values ('0304') ); insert into test2 values(1,'0302'); insert into test2 values(3,'0303'); insert into test2 values(6,'0304'); commit; SQL> set autotrace trace exp SQL> select * from test1 t1,test2 t2 where t1.id= t2.id and t1.bureau_code = t2.bureau_code and t1.bureau_code='0302'; 执行计划 ---------------------------------------------------------- Plan hash value: 3614704095 ---------------------------------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | Pstart| Pstop | ---------------------------------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 1 | 98 | 7 (15)| 00:00:01 | | | |* 1 | HASH JOIN | | 1 | 98 | 7 (15)| 00:00:01 | | | | 2 | PART JOIN FILTER CREATE| :BF0000 | 1 | 49 | 3 (0)| 00:00:01 | | | | 3 | PARTITION LIST SINGLE | | 1 | 49 | 3 (0)| 00:00:01 | 1 | 1 | | 4 | TABLE ACCESS FULL | TEST2 | 1 | 49 | 3 (0)| 00:00:01 | 1 | 1 | | 5 | PARTITION LIST SINGLE | | 2 | 98 | 3 (0)| 00:00:01 |KEY(AP)|KEY(AP)| | 6 | TABLE ACCESS FULL | TEST1 | 2 | 98 | 3 (0)| 00:00:01 | 1 | 1 | ---------------------------------------------------------------------------------------------------- Predicate Information (identified by operation id): --------------------------------------------------- 1 - access("T1"."BUREAU_CODE"="T2"."BUREAU_CODE" AND "T1"."ID"="T2"."ID") 用不上分区的情况: SQL> select * from test1 t1,test2 t2 where t1.id= t2.id(+) and t1.bureau_code = t2.bureau_code(+) and t2.bureau_code(+)='0302'; 执行计划 ----------------------------------------------------------Plan hash value: 311524636------------------------------------------------------------------------------------------------| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | Pstart| Pstop |------------------------------------------------------------------------------------------------| 0 | SELECT STATEMENT | | 6 | 588 | 10 (10)| 00:00:01 | | ||* 1 | HASH JOIN OUTER | | 6 | 588 | 10 (10)| 00:00:01 | | || 2 | PARTITION LIST ALL | | 6 | 294 | 6 (0)| 00:00:01 | 1 | 3 || 3 | TABLE ACCESS FULL | TEST1 | 6 | 294 | 6 (0)| 00:00:01 | 1 | 3 || 4 | PARTITION LIST SINGLE| | 1 | 49 | 3 (0)| 00:00:01 | 1 | 1 || 5 | TABLE ACCESS FULL | TEST2 | 1 | 49 | 3 (0)| 00:00:01 | 1 | 1 |------------------------------------------------------------------------------------------------Predicate Information (identified by operation id):--------------------------------------------------- 1 - access("T1"."ID"="T2"."ID"(+) AND "T1"."BUREAU_CODE"="T2"."BUREAU_CODE"(+)) (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |