将多个文件发送到WCF服务的最佳方法是什么？

首先,您需要某种“输入”对象,该对象将传递给包含图像和字符串值的WCF服务.注意Images属性是一个字节数组的数组;这样你可以包含多个图像.

[DataContract]
public class InputObject
{
    [DataMember]
    public byte[][] Images { get; set; }

    [DataMember]
    public string FirstValue { get; set; }

    [DataMember]
    public string SecondValue { get; set; }
}

接下来,您将需要一个WCF服务将返回的对象…

[DataContract]
public class ReturnObject
{
    [DataMember]
    public string FirstValue { get; set; }

    [DataMember]
    public string SecondValue { get; set; }
}

您的ServiceContract将如下所示.

[ServiceContract]
public interface IService1
{
    [OperationContract]
    ReturnObject UploadData ( InputObject input );
}

你的服务类就像这样.

public class Service1 : IService1
{
    public ReturnObject UploadData ( InputObject input )
    {
        // Do your thing with InputObject data

        ReturnObject returnObject = new ReturnObject
                                        {
                                            FirstValue = "MyFirstValue",SecondValue = "MySecondValue"
                                        };

        return returnObject;
    }
}

您需要确保服务的绑定适合发送图像数据,因此增加一些默认限制是合适的.这是我服务配置的绑定示例.

<wsHttpBinding>
  <binding name="Service1Binding" maxReceivedMessageSize="1000000">
    <readerQuotas maxArrayLength="1000000"
                  maxBytesPerRead="1000000"
                  maxDepth="1000000"
                  maxNameTableCharCount="1000000"
                  maxStringContentLength="1000000"/>
  </binding>
</wsHttpBinding>

确保将此指定为您的服务的bindingConfiguration.

<endpoint address="" 
          binding="wsHttpBinding" 
          contract="WcfService5.IService1" 
          bindingConfiguration="Service1Binding">

现在您需要做的就是从客户端的服务中引用它并调用它.

var images = new byte[2][];
images[0] = System.IO.File.ReadAllBytes( @"D:DevelopmentTestImage.bmp" );
images[1] = System.IO.File.ReadAllBytes( @"D:DevelopmentTestImage.jpg" );

var input = new InputObject
                {
                    Images = images,FirstValue = "MyFirstValue",SecondValue = "MySecondValue"
                };

var client = new Service1Client();
client.UploadData( input );

希望这可以帮助你…