如何在保护角2中获取请求网址

发布时间：2020-12-17 17:42:27 所属栏目：安全来源：网络整理

导读：如何在警卫服务中获取请求网址 HasPermissionService @Injectable()export class HasPermissionService implements CanActivate{ private permissions = []; constructor(private _core:CoreService,private route1:Router,private _route:ActivatedRoute,pr

如何在警卫服务中获取请求网址

HasPermissionService

@Injectable()
export class HasPermissionService implements CanActivate{
  private permissions = [];

  constructor(private _core:CoreService,private route1:Router,private _route:ActivatedRoute,private route: ActivatedRouteSnapshot,private  state: RouterStateSnapshot) { 
    console.log('constructor calling ...');
    // console.log(this.route.url);
    this.permissions = this._core.getPermission();
    console.log('inside guard');
    console.log(this.permissions);
  }

  canActivate( ) {
    console.log(this.route);
    console.log(this._route);
    return true;
  }
}

但是我正在变老,我来自哪里.如何获取当前网址？

路线

{path:'grade-listing',component:GradeListingComponent,canActivate:[HasPermissionService]}

我需要获得’等级列表’

解决方法

在canActivate函数中,ActivatedRouteSnapshot和RouterStateSnapshot作为参数传递：

@Injectable()
export class HasPermissionService implements CanActivate {

   private permissions = [];

   constructor(private _core: CoreService) { 
     this.permissions = this._core.getPermission();
   } 

   canActivate(
      route: ActivatedRouteSnapshot,state: RouterStateSnapshot
    ): Observable<boolean>|Promise<boolean>|boolean {
       //check here
    }
}

您应该从那里开始查看正在激活的路线

CanActivate

（编辑：李大同）

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