如何在测试中模拟Angular 4.3 httpClient的错误响应
发布时间:2020-12-17 09:41:27 所属栏目:安全 来源:网络整理
导读:我有一个下面的拦截器auth-interceptor.service.ts import {Injectable,Injector} from '@angular/core';import {HttpErrorResponse,HttpEvent,HttpHandler,HttpInterceptor,HttpRequest} from '@angular/common/http';import {Observable} from 'rxjs/Obser
|
我有一个下面的拦截器auth-interceptor.service.ts
import {Injectable,Injector} from '@angular/core';
import {HttpErrorResponse,HttpEvent,HttpHandler,HttpInterceptor,HttpRequest} from '@angular/common/http';
import {Observable} from 'rxjs/Observable';
import {Cookie} from './cookie.service';
import {Router} from '@angular/router';
import {UserService} from './user.service';
import {ToasterService} from '../toaster/toaster.service';
import 'rxjs/add/operator/catch';
import 'rxjs/add/observable/throw';
@Injectable()
export class AuthInterceptor implements HttpInterceptor {
constructor(private injector: Injector) {}
private handleError(err: HttpErrorResponse): Observable<any> {
let errorMsg;
if (err.error instanceof Error) {
// A client-side or network error occurred. Handle it accordingly.
errorMsg = `An error occurred: ${err.error.message}`;
} else {
// The backend returned an unsuccessful response code.
// The response body may contain clues as to what went wrong,errorMsg = `Backend returned code ${err.status},body was: ${err.error}`;
}
if (err.status === 401 || err.status === 403) {
this.injector.get(UserService).purgeAuth();
this.injector.get(ToasterService).showError(`Unauthorized`,errorMsg);
this.injector.get(Router).navigateByUrl(`/login`);
}
console.error(errorMsg);
return Observable.throw(errorMsg);
}
intercept(req: HttpRequest<any>,next: HttpHandler): Observable<HttpEvent<any>> {
// Clone the request to add the new header.
const authReq = req.clone({headers: req.headers.set(Cookie.tokenKey,Cookie.getToken())});
// Pass on the cloned request instead of the original request.
return next.handle(authReq).catch(err => this.handleError(err));
}
}
现在我试图模拟http.get来抛出错误,因此方法handleError控制错误消息. 下面是我对测试用例auth-interceptor.service.specs.ts的方法 import {async,inject,TestBed} from '@angular/core/testing';
import {AuthInterceptor} from './auth-interceptor.service';
import {ApiService} from './api.service';
import {HttpClientTestingModule,HttpTestingController} from '@angular/common/http/testing';
import {environment} from '../../../environments/environment';
describe(`AuthInterceptor`,() => {
const somePath = `/somePath`;
beforeEach(() => {
TestBed.configureTestingModule({
imports: [HttpClientTestingModule],providers: [AuthInterceptor,ApiService]
});
});
it(`should be created`,inject([AuthInterceptor],(service: AuthInterceptor) => {
expect(service).toBeTruthy();
}));
it(`should log an error to the console on error on get()`,async(inject([ApiService,HttpTestingController],(apiService: ApiService,httpMock: HttpTestingController) => {
spyOn(console,'error');
apiService.get(somePath).subscribe((res) => {
console.log(`in success:`,res);
},(error) => {
console.log(`in error:`,error);
});
const req = httpMock.expectOne(`${environment.apiUri}${somePath}`);
req.flush({
type: 'ERROR',status: 404,body: JSON.stringify({color: `blue`})
});
expect(console.error).toHaveBeenCalled();
}))
);
});
在刷新响应时,我不确定如何刷新错误响应,以便在我的拦截器中调用方法handleError,最终调用console.error.文档没有我的情况的任何例子.任何帮助或建议表示赞赏.
HttpTestingController类中的expectOne方法返回一个TestRequest对象.此TestRequest类具有可用于传递的flush方法
我们可以通过返回一个正文以及一些额外的响应头(如果有的话)来解决请求.相关信息可以在here找到. 现在,回过头来说明如何做到这一点.您可以根据您的使用情况自定义以下代码段. http = TestBed.get(HttpTestingController);
let response:any;
let errResponse: any;
const mockErrorResponse = {
status: 404,statusText: 'Bad Request'
};
const data = 'Invalid request parameters';
apiService.get(somePath).subscribe(res => response=res,err => errResponse=err);
http.expectOne('url/being/monitored').flush(data,mockErrorResponse);
expect(errResponse).toBe(data);
注意:在撰写此注释时,mockErrorResponse中需要statusText.相关信息可以在here找到. P.S.:TestRequest类的错误方法可用于在我们的测试用例中模拟网络错误,因为它需要一个Error实例.以下代码段显示了这一点. http.expectOne(someUrl).error(new ErrorEvent('network error'));
(编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
