《Angular4之Typescript用法》

前言：

随着Angular的深入实践，对于typescript用法一些细节之处很值得去总结的，请随小编一起来看看吧。

正文：

find

this.eachName = this.allCount.find(x => x.id == Id).index;

forEach

this.questionTypeSetModels.forEach(
      sc => {
        this.sum = (Number)(this.sum) + (Number)(sc.questionTypeScore);
      }
    )

RemoveQuestionTypeRecord(index): void {
    this.disabled.splice(index,1);
    this.isShowArray.splice(index,1);
    this.questionTypeSetModels.splice(index,1);
  }

filter

//选择班级id,根据班级id查询学生
  //ITOO-FrontEndsrcappworkspaceexam-manageexam-configureexam-configure-byhandbind-exam-studentbind-exam-student.component.ts
  selectClass(id: string,capnum:string,checked: boolean) {  
    var index: number = this.classIds.indexOf(id);
    var indexCap:number=this.capacitys.indexOf(capnum)
    if (checked) {
      if (index < 0) {
        this.classIds.push(id);
        this.capacitys.push(capnum);
      }
    } else {
      if (index > -1) {
        this.classIds = this.classIds.filter((ele,index) => {
          return ele != id;
        })
        this.capacitys=this.capacitys.filter((ele,indexCap) => {
          return ele != capnum;
        })
      }
    }
    console.log(this.classIds)
    if(this.classIds.length<=0){
      this.studentList=[];
    }
    else{
      //根据班级id数组查询有多少学生
      this.getStudent(this.classIds)
    }
  }

concat

ITOO-FrontEndsrcappworkspaceexamination-questions-managetemplate-managequestion-type-score-infocustom-settingscustom-settings.component.ts

coustomQuestion = this.questionTypeScoreInfoModels.concat(this.mustQuestionList);

结语：

点滴积累，大大提升开发效率