AngularJS.返回新的工厂实例
发布时间:2020-12-17 07:54:13 所属栏目:安全 来源:网络整理
导读:我是AngularJS的新手并且遇到过这个问题. 我可以在所有控制器上重新注入我的工厂单例对象吗? 例如: .factory('medicalCenterService',function(MedicalCenterResource) { var medicalCenterService = {}; medicalCenterService.currentMedCenter = Medical
我是AngularJS的新手并且遇到过这个问题.
我可以在所有控制器上重新注入我的工厂单例对象吗? 例如: .factory('medicalCenterService',function(MedicalCenterResource) { var medicalCenterService = {}; medicalCenterService.currentMedCenter = MedicalCenterResource.get(); medicalCenterService.reloadMedCenter = function() { medicalCenterService.currentMedCenter = MedicalCenterResource.get(); return medicalCenterService.currentMedCenter; }; medicalCenterService.updateMedicalCenter = function(medicalCenter) { MedicalCenterResource.updateMedicalCenter(medicalCenter); medicalCenterService.currentMedCenter = medicalCenter; }; return medicalCenterService; }) 在MedicalCenterController中,我在应用程序启动时获得带医疗中心的单例对象: function MedicalCenterController($scope,medicalCenterService) { $scope.currentMedCenter = medicalCenterService.currentMedCenter; } 但后来我尝试在AccountProfileController中编辑医疗中心字段(名称,地址等) function AccountProfileController($scope,medicalCenterService) { $scope.currentMedCenter = medicalCenterService.currentMedCenter; $scope.applyMedCenterChanges = function (currentMedCenter) { medicalCenterService.updateMedicalCenter(currentMedCenter); }; } 而我期望拥有的是具有更新字段的对象.
你想要这样的东西吗?
.factory('MedicalCenter',function(MedicalCenterResource) { var MedicalCenter = function () { var center = MedicalCenterResource.get(),update = function() { MedicalCenterResource.updateMedicalCenter(center) }; return { center: center,update: update } }; return MedicalCenter; }) function MedicalCenterController($scope,MedicalCenter) { center = new MedicalCenter(); $scope.currentMedCenter = center.center; } function AccountProfileController($scope,MedicalCenter) { center = new MedicalCenter(); $scope.currentMedCenter = center.center; $scope.applyMedCenterChanges = function () { center.update(); }; } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |