Axis 简单说明
发布时间:2020-12-17 01:28:27 所属栏目:安全 来源:网络整理
导读:? 1,axis本身可以servlet的形式集成到任何支持servlet的Web容器(web.xml) - ? servlet ? ? display-name Apache-Axis Servlet / display-name ? ? servlet-name AxisServlet / servlet-name ? ? servlet-class org.apache.axis.transport.http.AxisServle
? 1,axis本身可以servlet的形式集成到任何支持servlet的Web容器(web.xml)
-?
<
servlet
>
??
<
display-name
>
Apache-Axis Servlet
</
display-name
>
??
<
servlet-name
>
AxisServlet
</
servlet-name
>
??
<
servlet-class
>
org.apache.axis.transport.http.AxisServlet
</
servlet-class
>
??
</
servlet
>
2,当然需要让Web容器找到org.apache.axis.transport.http.AxisServlet
-?
<
servlet-mapping
>
??
<
servlet-name
>
AxisServlet
</
servlet-name
>
??
<
url-pattern
>
*.jws
</
url-pattern
>
??
</
servlet-mapping
>
-?
<
servlet-mapping
>
??
<
servlet-name
>
AxisServlet
</
servlet-name
>
??
<
url-pattern
>
/services/*
</
url-pattern
>
??
</
servlet-mapping
>
4,剩下的只需要告诉axis每个WebService对应着哪个Java类即可(server-config.wsdd(与web.xml同目录))
-?
<
service name
="
OrganizationWebService
"
?type
=""
?provider
="
java:RPC
"
?style
="rpc
"
?use
="encoded
">
??
<
parameter?
name
="scope
"
?value
="Request
" />
??
<
parameter?
name
="
className
"
?value
="
nucleus.organization.webservice.OrganizationWebService
" />
??
<
parameter?
name
="
allowedMethods
"
?value
="
isValid,personOfID,personsOfRole,queryCategories,queryPersons
" />
??
<
namespace
>http://webservice.organization.nucleus
</
namespace
>
??
<
typeMapping?
encodingStyle
="http://schemas.xmlsoap.org/soap/encoding/
"
?qname
="ns1:CategoryInfo
"
?languageSpecificType
="java:nucleus.organization.webservice.CategoryInfo
"
?serializer
="org.apache.axis.encoding.ser.BeanSerializerFactory
"
?deserializer
="org.apache.axis.encoding.ser.BeanDeserializerFactory
"
?name
="CategoryInfo
"
?xmlns:ns1
="
http://webservice.organization.nucleus
" />
??
</
service
>
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