方案一:WebService
资料来源:http://jingyan.baidu.com/article/b7001fe157d6b60e7382dd7f.html
简介:
WinForm都是运行在本地的,而我们的网站一般都是布署在服务器上,运行在服务器上的,所以在网站上面上传文件,就好似于保存文件到本地。但在WinForm上就不一样了,本章我们简单举一个在WinForm利用WebService上传文件到服务器的方法。
步骤一:
首先们先创建一个WebService服务,该服务包含一个UpdateFile方法,该方法接收两个byte[]与string类型参数。
该方法非常简单,就是按照string参数指定的路径和名称将byte[]参数值保存到服务器,代码如下:
??[WebMethod(Description = "上传文件")]
??[Erp7Extension(Compress =true)]
??[SoapHeader("header")]
??public void UploadFiles(string userID,string fileName,byte[] file)
??{
???int rst=WsUploadFile(userID,fileName,file);
??}
??
??/// <summary>
??///
??/// </summary>
??/// <param name="userId"></param>
??/// <param name="fileName">D:Tempxx.后缀名</param>
??/// <param name="fileContent"></param>
??/// <returns></returns>
??[WebMethod]
??private int WsUploadFile(string userId,byte[] fileContent)
??{
???try
???{
?????????? //要上传到webservice发布的服务器的D盘中Temp文件夹,且上传之后的文件名参数fileName
???????????string filePath = @"D:Temp" + fileName;
????????????//方式1:
????????????StreamWriter sw = new StreamWriter(filePath);
????????????sw.Write(fileContent);
????????????sw.Close();
????????????//方式2:
????????????File.WriteAllBytes(filePath,fileContent);
????????????return 1;
???}
???catch
???{
????return 0;
???}
??}
步骤一:
WinForm调用,代码如下:
??/// <summary>
??/// WebService上传
??/// </summary>
??/// <param name="sender"></param>
??/// <param name="e"></param>
??private void simpleButton2_Click(object sender,EventArgs e)
??{
????????? string iniPath = DataConvert.ToString(btnOpenDialog.EditValue);
????????????if (iniPath.Length == 0)
????????????{
??????????????????????XtraMessageBox.Show("请选择要上传的文件!");
??????????????????????return;
????????????}
????????????// 要上传的文件?
????????????FileStream file = new FileStream(iniPath,FileMode.Open,FileAccess.Read);
????????????byte[] bytes = new byte[file.Length];
???????????//读取文件保存到字节流对象
????????????file.Read(bytes,bytes.Length);
?????????? string userID=“admin”;
????????????string fileNewName = "Ws_Ys.rar"; ????????????IFtmBasFiles ftmBasfiles = FtmBasFilesFactory.Owner.Create(); ????????????ftmBasfiles.UploadFiles(userID,fileNewName,bytes); ??}