Webservice_16_SOAP的handler简介

非常感谢孙浩老师。

LogicalHandler和SOAPHandler
LogicalHandler只能获取SOAPBody的信息
SOAPHandler可以获取SOAPMessage的信息
处理顺序

SOAPHandler

创建自定义handler，实现SOAPHandler<SOAPMessageContext>，复写方法和输入语句标识：

package cn.lichen.handler;

import java.util.Set;

public class HeardHandler implements SOAPHandler<SOAPMessageContext> {

	@Override
	public boolean handleMessage(SOAPMessageContext context) {
		System.out.println("handleMessage.....");
		return true;
	}

	@Override
	public boolean handleFault(SOAPMessageContext context) {
		System.out.println("handleFault.....");
		return false;
	}

	@Override
	public void close(MessageContext context) {
		
	}

	@Override
	public Set<QName> getHeaders() {
		return null;
	}

}

配置handler-chain.xml:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<javaee:handler-chains 
     xmlns:javaee="http://java.sun.com/xml/ns/javaee" 
     xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <javaee:handler-chain>
    <javaee:handler>
      <javaee:handler-class>cn.lichen.handler.HeardHandler</javaee:handler-class>
    </javaee:handler>
  </javaee:handler-chain>
</javaee:handler-chains>

?

测试方法一：

public static void main(String[] args) {
		MyServiceImplService mis = new MyServiceImplService();
		IMyService ms = mis.getMyServiceImplPort();
		try {
			ms.login("admin","123");
			System.out.println("TestClient......");
		} catch (UserException_Exception e) {
			System.out.println(e.getMessage());
		}
	}

?

登入成功，没抛异常：

说明没有进入handleFault方法，和handler方法会像过滤器一样执行两次。

测试方法一：

package cn.lichen.soap;

public class TestClient {

	public static void main(String[] args) {
		MyServiceImplService mis = new MyServiceImplService();
		IMyService ms = mis.getMyServiceImplPort();
		try {
			ms.login("admin","111");
			System.out.println("TestClient......");
		} catch (UserException_Exception e) {
			System.out.println(e.getMessage());
		}
	}
}

登入失败，抛异常：

?

说明进入handleFault方法，停止执行。