ws问题总结（二）

1、a? > 建一个web项目，添加完spring+hibernate的jar包以后，添加jax-ws 2.1等jar路径；

???? ?b? >? 然后写一个java类，带上@WebService和@WebMethod，

????? c? >? 使用Myeclipse自动生成WS，会自动生成wsdl、web.xml中的配置等，applicationContext.xml中不用额外配置；

????? （加上@，则不会生成TgsFuncitonDelegate）

????? d? >? ?在spring中，toTell中注入private WSAction wsaction，wsaction使用时报空指针，实例化toTell时wsaction没有注入成功，需要这样得到wsaction

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    ApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");

????WSAction wsaction= (TgsPassedCarAction)context.getBean("WSAction");

e? >? （jar包：spring? +?

????????????????????? ?hibernate? +?

????????????????????? ?jax-ws 2.1 RunTime Liberaries? +?

???????????????????? ? jax-ws 2.1 API Liberaries）

----------------------------------------------------------web.xml中自动生成的部分---------------------------------------------------------------------------------------------------------

-------------------------------------还有记得是WSServlet，不要和后边的WSSpringServlet混了----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" 
	xmlns="http://java.sun.com/xml/ns/javaee" 
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
	xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
	http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
  <display-name></display-name>	
 <span style="color:#ff0000;"> <listener>
  	<listener-class>
  		com.sun.xml.ws.transport.http.servlet.WSServletContextListener
  	</listener-class>
  </listener>
</span>  <servlet>
  	<description>JAX-WS endpoint - toDoService</description>
  	<display-name>toDoService</display-name>
  	<servlet-name>toDoService</servlet-name>
  	<servlet-class>
  		<span style="color:#ff0000;">com.sun.xml.ws.transport.http.servlet.WSServlet</span>
  	</servlet-class>
  	<load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
  	<servlet-name>toDoService</servlet-name>
  	<url-pattern>/toDoPort</url-pattern>
  </servlet-mapping>
</web-app>

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2、通过spring注入的方式，而不用再context.getBean()的方式获得注入的bean组件，更加方便

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????????? a? >? 首先加上Spring+jax-ws整合所需要的jar包，见下面，spring和hibernate的jar包随意加；

??????? ? b? >? 写一个java类，要加上@WebService(targetNamespace = "org.coderecord.blog")，括号里的没加的话，我这里报错（Caused by: com.sun.xml.ws.model.RuntimeModelerException: 必须在没有程序包的类上指定 @WebService.targetNamespace。类: Test）；

???????????????? @WebMethod(exclude = true)使get/set方法对外不可见；

	<p>	import javax.jws.WebMethod;
	import javax.jws.WebService;</p><p>	@WebService(targetNamespace = "org.coderecord.blog")
	public class Test {
?	private TestBean testBean;
?	@WebMethod
?	public String toTest(String name){
?	?String daming = testBean.tosat("lvlvlv");
?	?System.out.println(name+": "+daming);
?	?return name+":"+daming;
?	}
?	@WebMethod(exclude = true)
?	public TestBean getTestBean() {
?	?return testBean;
?	}
	?@WebMethod(exclude = true)
	?public void setTestBean(TestBean testBean) {
?	?this.testBean = testBean;
	?}
	}</p>

??????????????c? >? ?接着，applicationContext.xml中，手动配置

	<?xml version="1.0" encoding="UTF-8"?>
  	<beans xmlns="http://www.springframework.org/schema/beans"
 	     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" <span style="color:#ff0000;">xmlns:ws="http://jax-ws.dev.java.net/spring/core"
</span>  	   <span style="color:#ff0000;"> xmlns:wss="http://jax-ws.dev.java.net/spring/servlet"</span> xmlns:p="http://www.springframework.org/schema/p"
  	    xmlns:context="http://www.springframework.org/schema/context"
  	    xsi:schemaLocation="http://www.springframework.org/schema/beans
   	   http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
   	   http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.2.xsd
  	   <span style="color:#ff0000;"> http://jax-ws.dev.java.net/spring/core
  	   http://jax-ws.dev.java.net/spring/core.xsd
  	   http://jax-ws.dev.java.net/spring/servlet
  	   http://jax-ws.dev.java.net/spring/servlet.xsd"></span>
     
  	   <bean id="test" class="Test">
  	   	<property name="testBean">
   	  		<ref bean="testBean"/>
   	  	</property>
  	   </bean>
  	   <bean id="testBean" class="TestBean"></bean>
 
   	 <span style="color:#ff0000;"> <wss:binding url="/service/test">
   	      <wss:service>
   	          <ws:service bean="#test" />
   	      </wss:service>
  	   </wss:binding>
	</span></beans>

??????????? d? >? web.xml中手动配置，注意下面红色的代码和第一种jax-ws写法中的WSServlet 不是一个Servlet

	<?xml version="1.0" encoding="UTF-8"?>
	<web-app version="3.0" 
		xmlns="http://java.sun.com/xml/ns/javaee" 
		xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
		xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
		http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
	  <display-name></display-name>	
 	  <context-param>
 	   <param-name>contextConfigLocation</param-name>
 	   <param-value>/WEB-INF/classes/*Context.xml</param-value>
 	 </context-param>
 	 <listener>
 	   <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
 	 </listener>
	  <servlet>
 	   <description>JAX-WS endpoint - test</description>
   	 <display-name>testService</display-name>
  	  <servlet-name>testService</servlet-name>
  	  <span style="color:#ff0000;"><servlet-class>com.sun.xml.ws.transport.http.servlet.WSSpringServlet</servlet-class>
</span>  	  <load-on-startup>1</load-on-startup>
 	 </servlet>
 	 <servlet-mapping>
  	  <servlet-name>testService</servlet-name>
  	  <url-pattern>/service/test</url-pattern>
 	 </servlet-mapping>
 	 <welcome-file-list>
  	  <welcome-file>index.jsp</welcome-file>
 	 </welcome-file-list>
	</web-app>

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