如何在Scala实体上运行Hibernate的JPAMetaModelEntityProcessor

<dependency>
    <groupId>org.hibernate</groupId>
    <artifactId>hibernate-jpamodelgen</artifactId>
    <version>1.1.1.Final</version>
</dependency>

但是,对于用Scala编写的实体来说,这当然是失败的.我试图使用maven-processor-plugin“手动”生成元模型,我的pom.xml看起来像这样：

<plugin>
    <groupId>org.bsc.maven</groupId>
    <artifactId>maven-processor-plugin</artifactId>
    <executions>
        <execution>
            <id>process</id>
            <goals>
                <goal>process</goal>
            </goals>
            <phase>generate-sources</phase>
            <configuration>
                <processors>
                    <!-- list of processors to use -->
                    <processor>org.hibernate.jpamodelgen.JPAMetaModelEntityProcessor</processor>
                </processors>
                <!-- source output directory -->
                <outputDirectory>target/metamodel</outputDirectory>
            </configuration>
        </execution>
    </executions>
</plugin>
<plugin>
    <groupId>org.codehaus.mojo</groupId>
    <artifactId>build-helper-maven-plugin</artifactId>
    <version>1.3</version>
    <executions>
        <execution>
            <id>add-source</id>
            <phase>generate-sources</phase>
            <goals>
                <goal>add-source</goal>
            </goals>
            <configuration>
                <sources>
                    <source>target/metamodel</source>
                </sources>
            </configuration>
        </execution>
    </executions>
</plugin>

但没有任何反应.

有人已经用Scala编写的JPA实体成功生成了JPA元模型吗？

谢谢.