scala case类私有应用方法(repl bug？)

Welcome to Scala version 2.10.0 (Java HotSpot(TM) 64-Bit Server VM,Java 1.7.0_13).
Type in expressions to have them evaluated. 
Type :help for more information.

scala> case class A private(i:Int)
defined class A

scala> A(1)
res0: A = A(1)

但如果编译

$scala -version
Scala code runner version 2.10.0 -- Copyright 2002-2012,LAMP/EPFL
$cat Main.scala 
package foo

case class A private (i:Int)

object Main extends App{
  println(A(1))
}

$scalac Main.scala 
Main.scala:6: error: constructor A in class A cannot be accessed in object Main
  println(A(1))
          ^
one error found

A.apply(1)是编译错误.

这个Scala2.10.0 REPL错误？

FYI Scala2.9.2 REPL如下

Welcome to Scala version 2.9.2 (Java HotSpot(TM) 64-Bit Server VM,Java 1.7.0_13).
Type in expressions to have them evaluated.
Type :help for more information.

scala> case class A private(i:Int)
defined class A

scala> A(1)
<console>:10: error: constructor A in class A cannot be accessed in object $iw
              A(1)
              ^