如何在Scala中对Python或运算符进行近似设置比较？

这是整个问题. (我们还不比较代码行.)

(两个注意事项：如果您愿意,可以在Scala解释器中运行它.如果您需要big.txt或整个项目的副本,则为on GitHub.)

import scala.io.Source

val alphabet = "abcdefghijklmnopqrstuvwxyz"

def train(text:String) = {
  "[a-z]+".r.findAllIn(text).foldLeft(Map[String,Int]() withDefaultValue 1)
    {(a,b) => a(b) = a(b) + 1}
}

val NWORDS = train(Source.fromFile("big.txt").getLines.mkString.toLowerCase)

def known(words:Set[String]) =
  {Set.empty ++ (for(w <- words if NWORDS contains w) yield w)}

def edits1(word:String) = {
  Set.empty ++
  (for (i <- 0 until word.length) // Deletes
    yield (word take i) + (word drop (i + 1))) ++ 
  (for (i <- 0 until word.length - 1) // Transposes
    yield (word take i) + word(i + 1) + word(i) + (word drop (i + 2))) ++ 
  (for (i <- 0 until word.length; j <- alphabet) // Replaces
    yield (word take i) + j + (word drop (i+1))) ++ 
  (for (i <- 0 until word.length; j <- alphabet) // Inserts
    yield (word take i) + j + (word drop i))
}

def known_edits2(word:String) = {Set.empty ++ (for (e1 <- edits1(word);
  e2 <- edits1(e1) if NWORDS contains e2) yield e2)}

def correct(word:String) = {
  val options = Seq(() => known(Set(word)),() => known(edits1(word)),() => known_edits2(word),() => Set(word))
  val candidates = options.foldLeft(Set[String]())
    {(a,b) => if (a.isEmpty) b() else a}
  candidates.foldLeft("") {(a,b) => if (NWORDS(a) > NWORDS(b)) a else b}
}

具体来说,我想知道我能用正确的功能做些什么更清洁.在原始Python中,实现更清晰：

def correct(word):
    candidates = known([word]) or known(edits1(word)) or
      known_edits2(word) or [word]
    return max(candidates,key=NWORDS.get)

显然在Python中,空集将评估为布尔值False,因此只会评估返回非空集的第一个候选项,从而节省对edits1和known_edits2的潜在昂贵调用.

我想出的唯一解决方案是你在这里看到的版本,其中匿名函数的Seq被调用,直到一个返回一个非空的Set,最后一个保证做.

经验丰富的Scala主管,是否有更复杂的语法或更好的方法呢？提前致谢！