scala – 处理Akka演员的错误

但是如果演员必须处理错误呢？我有另一个Actor(SimpleActorWithFault).这个演员可能有错.在这种情况下,我通过抛出异常来生成一个.当发生故障时(即SimpleActorWithFault抛出异常),它会自动重启.但是,这次重启会扰乱Actor内部的调度程序,该调度程序不再作为例外.如果故障发生得足够快,就会产生更多的意外行为.

我的问题是在这种情况下处理故障的首选方法是什么？我知道我可以使用Try块来处理异常.但是,如果我扩展另一个演员,我不能在超类中放置一个演员,或者某些情况下,当我是一个例外的故障发生在演员身上.

import akka.actor.{Props,ActorLogging}
import scala.concurrent.ExecutionContext.Implicits.global
import scala.concurrent.duration._
import akka.actor.Actor

case object MessageA

case object MessageToSelf


class SimpleActor extends Actor with ActorLogging {

  //schedule a message to self every second
  context.system.scheduler.schedule(0 seconds,1 seconds,self,MessageToSelf)

  //keeps track of some internal state
  var count: Int = 0

  def receive: Receive = {
    case MessageA => {
      log.info("[SimpleActor] Got MessageA at %d".format(count))
    }
    case MessageToSelf => {
      //update state and tell the world about its current state 
      count = count + 1
      log.info("[SimpleActor] Got scheduled message at %d".format(count))

    }
  }

}


class SimpleActorWithFault extends Actor with ActorLogging {

  //schedule a message to self every second
  context.system.scheduler.schedule(0 seconds,MessageToSelf)

  var count: Int = 0

  def receive: Receive = {
    case MessageA => {
      log.info("[SimpleActorWithFault] Got MessageA at %d".format(count))
    }
    case MessageToSelf => {
      count = count + 1
      log.info("[SimpleActorWithFault] Got scheduled message at %d".format(count))

      //at some point generate a fault
      if (count > 5) {
        log.info("[SimpleActorWithFault] Going to throw an exception now %d".format(count))
        throw new Exception("Excepttttttiooooooon")
      }
    }
  }

}


object MainApp extends App {
  implicit val akkaSystem = akka.actor.ActorSystem()
  //Run the Actor without any faults or exceptions 
  akkaSystem.actorOf(Props(classOf[SimpleActor]))

  //comment the above line and uncomment the following to run the actor with faults  
  //akkaSystem.actorOf(Props(classOf[SimpleActorWithFault]))

}