比较两个字符串时如何使scalatest匹配器忽略空格？

发布时间：2020-12-16 18:53:53 所属栏目：安全来源：网络整理

导读：我有以下测试 "Matchers" should "ignore whitespace if configured so" in { " aaa n nr bbb".replaceAll("s+"," ") shouldBe "naaa bbb".replaceAll("s+"," ") } 有一种最神奇的惯用方法吗？解决方法我发现在 http://www.scalatest.org/user_gui

我有以下测试

"Matchers" should "ignore whitespace if configured so" in {
    " aaa n nr bbb".replaceAll("s+"," ") shouldBe "naaa bbb".replaceAll("s+"," ")
  }

有一种最神奇的惯用方法吗？

解决方法

我发现在 http://www.scalatest.org/user_guide/using_matchers处对不区分大小写的比较进行了一些归一化

import org.scalatest.Matchers._
import org.scalactic.Explicitly._
import org.scalactic.StringNormalizations._
"Hi" should equal ("hi") (after being lowerCased)

我创建了以下规范化器

import org.scalactic._
val whiteSpaceNormalised: Uniformity[String] =
  new AbstractStringUniformity {
    /**Returns the string with all consecutive white spaces reduced to a single space.*/
    def normalized(s: String): String = s.replaceAll("s+"," ")
    override def toString: String = "whiteSpaceNormalised"
  }

现在测试了

import org.scalatest.Matchers._
import org.scalactic.Explicitly._
import org.scalactic.StringNormalizations._
" aaa n nr bbb " should equal("naaa bbb      t")(after being whiteSpaceNormalised)

（编辑：李大同）

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