scala – 流程组合和例外
发布时间:2020-12-16 18:46:19 所属栏目:安全 来源:网络整理
导读:如何捕获与#组合的外部流程的例外情况?等等.? scala import scala.sys.process._ scala try{ "throw " ! }catch{ case e: Exception = }res1: AnyVal = ()scala try{ "throw " # "ls" ! }catch{ case e: Exception = }Exception in thread "Thread-10" jav
如何捕获与#&&组合的外部流程的例外情况?等等.?
scala> import scala.sys.process._ scala> try{ "throw " ! }catch{ case e: Exception => } res1: AnyVal = () scala> try{ "throw " #&& "ls" ! }catch{ case e: Exception => } Exception in thread "Thread-10" java.io.IOException: Cannot run program "throw": error=2,No such file or directory 解决方法
你已经做到了.尝试
try { val x = "throw" #&& "ls" ! } catch { case x => println("caught") } 的!只是将异常记录到控制台,当你在REPL中看到它时有点混乱,但它不会崩溃. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |