在Scala中,我可以覆盖包含列表的具体字段并在子类中附加一些内容
发布时间:2020-12-16 18:44:36 所属栏目:安全 来源:网络整理
导读:这是我所拥有的类的简化: trait RequiredThings { val requiredThings: Seq[String]}class SimpleCalculator with RequiredThings { val requiredThings = List("a","b")}class ComplicatedCalculator extends SimpleCalculator with RequiredThings { self
这是我所拥有的类的简化:
trait RequiredThings { val requiredThings: Seq[String] } class SimpleCalculator with RequiredThings { val requiredThings = List("a","b") } class ComplicatedCalculator extends SimpleCalculator with RequiredThings { self: SimpleCalculator => override val requiredThings:List[String] = List("c") ::: self.requiredThings } 在这个版本中,我使用的是自我类型的注释,但我不是完全肯定的,这是要走的路.我想我可以通过将requiredThings转换为一个方法来实现它,但我想把它作为一个字段来尝试. 最终解决方案 trait RequiredThings { def requiredThings: Seq[String] } class SimpleCalculator with RequiredThings { def requiredThings = List("a","b") } class ComplicatedCalculator extends SimpleCalculator with RequiredThings { override def requiredThings:List[String] = List("c") ::: super.requiredThings } 解决方法
是的,尚未实现对通过自我类型“继承”的方法的超级调用.这将很快(稍微)改变.在此期间,您应该使用继承.
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