Scala本地回归？

发布时间：2020-12-16 18:26:53 所属栏目：安全来源：网络整理

导读：我刚刚发现以下闭包中的返回将从函数findPackage返回 def findPackage(name: String,suffix: Option[String] = None): Path = { logger.debug("Looking for package {} with suffix {}",name,suffix) val path: Path = using(Files.newDirectoryStream(appDi

我刚刚发现以下闭包中的返回将从函数findPackage返回

def findPackage(name: String,suffix: Option[String] = None): Path = {
    logger.debug("Looking for package {} with suffix {}",name,suffix)
    val path: Path = using(Files.newDirectoryStream(appDir)) {dirs =>
        for (val path <- dirs) {
            val matcher = packagePattern.matcher(path.getFileName.toString)
            if (matcher.matches() && matcher.group(1).equals(name))
                if (suffix.isDefined) {
                    if (matcher.group(2) != null && matcher.group(2).equals(suffix.get))
                        return path
                } else
                    return path
        }
        throw new PackageNotFoundException(this,suffix)
    }
    logger.debug("Found package is {}",path)
    path
}

我可以以某种方式做一个本地回报吗？谢谢.

解决方法

或者你可以摆脱你的循环并将其替换为你想要做的事情：“找到”

def findPackage(name: String,suffix)

    def matching(path : Path) : Boolean = {
        val matcher = packagePattern.matcher(path.getFileName.toString)
        matcher.matches && matcher.group(1).equals(name) && (!suffix.isDefined || (matcher.group(2) != null && matcher.group(2).equals(suffix.get))
    }

    val path: Path = using(Files.newDirectoryStream(appDir)) {dirs =>
       dirs find matching getOrElse {throw new PackageNotFoundException(this,suffix)}
    }

    logger.debug("Found package is {}",path)
    path
}

（编辑：李大同）

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