我可以使用Scala的内置xml处理程序忽略无效的XML字符吗？

In addition,XML 1.1 allows you to
have control characters in your
documents through the use of character
references. This concerns the control
characters #x1 through #x1F,most of
which are forbidden in XML 1.0. This
means that your document can now
include the bell character,like this:
. However,you still cannot have
these characters appear directly in
your documents; this violates the
definition of the mime type used for
XML (text/xml).

Xerces可以解析XML 1.1,但似乎期望实体而不是真正的0x12字符：

val s = "<?xml version='1.1'?><root>u0012</root>"
// causes An invalid XML character (Unicode: 0x12)
//XML.loadXML(xml.Source.fromString(s),XML.parser)

val u = "<?xml version='1.1'?><root>&#18;</root>"
val v = XML.loadXML(xml.Source.fromString(u),XML.parser)
println(v) // works

正如lavinio所建议的,您可以过滤掉无效字符.这在Scala中不占用太多行：

val in = new InputStream {
  val in0 = new FileInputStream("invalid.xml")
  override def read():Int = in0.read match { case 0x12=> read() case x=> x}
}
val x = XML.load(in)