期权匹配的Scala类型擦除
发布时间:2020-12-16 18:25:35 所属栏目:安全 来源:网络整理
导读:object Test { def main(args: Array[String]) { val list: List[Double] = List(1.0,2.0,3.0,4.0) val none = None case class Test() val test = Test() def f(x: Any) = x match { case _: Some[Test] = println("_ matched") case None = println("None
object Test { def main(args: Array[String]) { val list: List[Double] = List(1.0,2.0,3.0,4.0) val none = None case class Test() val test = Test() def f(x: Any) = x match { case _: Some[Test] => println("_ matched") case None => println("None matched") } f(list) f(none) f(test) } } 尝试编译上面的代码会导致“擦除”编译时警告. $>scalac Test.scala Test.scala:11: warning: non-variable type argument Test in type pattern Some[Test] is unchecked since it is eliminated by erasure case _: Some[Test] => println("_ matched") ^ one warning found 我读了这个备受推崇的Stackoverflow post,但我不明白这里的类型擦除. 解决方法
在jvm的运行时,没有Some [Test]或Some [String]只有Some [Any].所以你无法匹配某些[测试].
在这种情况下,您可以匹配某些内容,如下所示: case Some(e: Test) => println(s"$e matched") (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |