scala – 在Sangria中编组嵌套的自定义对象
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我有以下输入对象：
val BusinessInputType = InputObjectType[BusinessInput]("BusinessInput",List(
InputField("userId",StringType),InputField("name",InputField("address",OptionInputType(StringType)),InputField("phonenumber",InputField("email",InputField("hours",ListInputType(BusinessHoursInputType))
))
val BusinessHoursInputType = InputObjectType[BusinessHoursInput]("hours",List(
InputField("weekDay",IntType),InputField("startTime",InputField("endTime",StringType)
))
以下是定制编组定义的模型： case class BusinessInput(userId: String,name: String,address: Option[String],phonenumber: Option[String],email: Option[String],hours: Seq[BusinessHoursInput])
object BusinessInput {
implicit val manual = new FromInput[BusinessInput] {
val marshaller = CoercedScalaResultMarshaller.default
def fromResult(node: marshaller.Node) = {
val ad = node.asInstanceOf[Map[String,Any]]
System.out.println(ad)
BusinessInput(
userId = ad("userId").asInstanceOf[String],name = ad("name").asInstanceOf[String],address = ad.get("address").flatMap(_.asInstanceOf[Option[String]]),phonenumber = ad.get("phonenumber").flatMap(_.asInstanceOf[Option[String]]),email = ad.get("email").flatMap(_.asInstanceOf[Option[String]]),hours = ad("hours").asInstanceOf[Seq[BusinessHoursInput]]
)
}
}
}
case class BusinessHoursInput(weekDay: Int,startTime: Time,endTime: Time)
object BusinessHoursInput {
implicit val manual = new FromInput[BusinessHoursInput] {
val marshaller = CoercedScalaResultMarshaller.default
def fromResult(node: marshaller.Node) = {
val ad = node.asInstanceOf[Map[String,Any]]
System.out.println("HEY")
BusinessHoursInput(
weekDay = ad("weekDay").asInstanceOf[Int],startTime = Time.valueOf(ad("startTime").asInstanceOf[String]),endTime = Time.valueOf(ad("endTime").asInstanceOf[String])
)
}
}
}
我的问题是,当我有一个具有自定义编组的嵌套InputObject时,我没有看到在编组BusinessInput之前调用BusinessHoursInput的编组.我注意到这一点,因为在“BusinessInput”中“ad”的print语句之前,“Hey”的print语句从未执行过.当我尝试在DB中插入BusinessInput的hours字段时,这会导致后来出现问题,因为它无法将其转换为BusinessHoursInput对象.在Sangria中,是否无法在父对象编组之前自定义Marshal嵌套对象？ 解决方法
您可能正在使用BusinessInput作为参数类型.实际的隐式查找发生在Argument定义时,仅适用于BusinessInput类型.
由于FromInput是基于类型类的反序列化,因此需要显式定义嵌??套对象的反序列化之间的依赖关系.例如,您可以像这样重写反序列化器： case类BusinessInput(userId：String,name：String,address：Option [String],phonenumber：Option [String],email：Option [String],hours：Seq [BusinessHoursInput]) object BusinessInput {
implicit def manual(implicit hoursFromInput: FromInput[BusinessHoursInput]) = new FromInput[BusinessInput] {
val marshaller = CoercedScalaResultMarshaller.default
def fromResult(node: marshaller.Node) = {
val ad = node.asInstanceOf[Map[String,Any]]
BusinessInput(
userId = ad("userId").asInstanceOf[String],hours = hoursFromInput.fromResult(ad("hours").asInstanceOf[Seq[hoursFromInput.marshaller.Node]])
)
}
}
}
在这个版本中,我利用现有的FromInput [BusinessHoursInput]从原始输入反序列化BusinessHoursInput. 另外,作为替代方案,您可以通过利用现有的基于JSON的反序列化器来完全避免定义手动FromInput反序列化器.例如,在大多数情况下,circe的自动推导工作正常.您只需要这两个导入(在您定义参数的文件中)： import sangria.marshalling.circe._ import io.circe.generic.auto._ 这些导入将适当的FromInput实例放入范围.这些实例利用了circe自己的反序列化机制. （编辑：李大同） 【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容! |