scala – 具有内部案例类的case类的字符串列表
假设我有2个案例类:
case class Money(amount: Int,currency: String) case class Human(name: String,money: Money) 有没有一种很好的方法可以将一个字符串列表“翻译”为类Human?像: def superMethod[A](params: List[String]): A = ??? val params: List[Any] = List("john",100,"dollar") superMethod(params) // => Human("john",Money(100,"dollar")) 所以基本上我只在运行时知道类型A. 更新:我发现?我在寻找什么.看来我可以通过无形来做到这一点. example我在github找到了 解决方法
这是一个适用于泛型类A的实现.
它依赖于运行时反射(也就是说,可以在运行时将不同的TypeTag传递给方法).必须满足以下明显条件才能使用此方法: > A必须在类路径上,否则可以由使用的类加载器加载 实际的实现是在Deserializer对象中.然后是一个小小的演示. 解串器: import scala.reflect.runtime.universe.{TypeTag,Type} object Deserializer { /** Extracts an instance of type `A` from the * flattened `Any` constructor arguments,and returns * the constructed instance together with the remaining * unused arguments. */ private def deserializeRecHelper( flattened: List[Any],tpe: Type ): (Any,List[Any]) = { import scala.reflect.runtime.{universe => ru} // println("Trying to deserialize " + tpe + " from " + flattened) // println("Constructor alternatives: ") // val constructorAlternatives = tpe. // member(ru.termNames.CONSTRUCTOR). // asTerm. // alternatives.foreach(println) val consSymb = tpe. member(ru.termNames.CONSTRUCTOR). asTerm. alternatives(0). asMethod val argsTypes: List[Type] = consSymb.paramLists(0).map(_.typeSignature) if (tpe =:= ru.typeOf[String] || argsTypes.isEmpty) { val h :: t = flattened (h,t) } else { val args_rems: List[(Any,List[Any])] = argsTypes.scanLeft( (("throwaway-sentinel-in-deserializeRecHelper": Any),flattened) ) { case ((_,remFs),t) => deserializeRecHelper(remFs,t) }.tail val remaining: List[Any] = args_rems.last._2 val args: List[Any] = args_rems.unzip._1 val runtimeMirror = ru.runtimeMirror(getClass.getClassLoader) val classMirror = runtimeMirror.reflectClass(tpe.typeSymbol.asClass) val cons = classMirror.reflectConstructor(consSymb) // println("Build constructor arguments array for " + tpe + " : " + args) val obj = cons.apply(args:_*) (obj,remaining) } } def deserialize[A: TypeTag](flattened: List[Any]): A = { val (a,rem) = deserializeRecHelper( flattened,(implicitly: TypeTag[A]).tpe ) require( rem.isEmpty,"Superfluous arguments remained after deserialization: " + rem ) a.asInstanceOf[A] } } 演示: case class Person(id: String,money: Money,pet: Pet,lifeMotto: String) case class Money(num: Int,currency: String) case class Pet(color: String,species: Species) case class Species(description: String,name: String) object Example { def main(args: Array[String]): Unit = { val data = List("Bob",42,"USD","pink","invisible","unicorn","what's going on ey?") val p = Deserializer.deserialize[Person](data) println(p) } } 输出: Person(Bob,Money(42,USD),Pet(pink,Species(invisible,unicorn)),what's going on ey?) 讨论 此实现不仅限于case类,但它要求每个“Tree-node-like”类只有一个接受它的构造函数 >原始类型(Int,Float),或 请注意,该任务有点不合理:说所有构造函数参数在单个列表中被展平是什么意思?给定Person类(name:String,age:Int),List [Any]是否会将名称的每个字节都包含在一个单独的条目中?可能不是.因此,字符串由解串器以特殊方式处理,并且由于相同的原因而不支持所有其他类似集合的实体(不清楚在何处停止解析,因为集合的大小未知). (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |