scala – 将HList中的验证应用于案例类

在尝试使用应用程序仿函数( Monad to catch multiple exceptions (not just fail on single))进行验证时,我在scalaz中遇到了一个不允许超过14个仿函数的硬限制,因此这里有用的评论( https://github.com/scalaz/scalaz/issues/504#issuecomment-23626237)导航我使用HLists而不是applicative functors

现在它工作得很好(从此处手动输入此序列文件,因为它不在maven https://github.com/typelevel/shapeless-contrib/blob/master/scalaz/main/scala/sequence.scala?source=c)

我的问题是,我知道这是可能的,你将如何自动实例化案例类Foo(i：Int,s：String)而无需手动将模式与案例匹配,只是再次重新应用参数

基本上我想做这样的事情

case class Foo(i:Int,s:String)

  implicit def TwoFoo = Iso.hlist(Foo.apply _,Foo.unapply _)

  val someFoo = sequence(
      1.successNel[Int] ::
      "2".successNel[String] ::
      HNil
  ).map { Foo.apply _} // Note this doesn't work

  someFoo match {
    case Success(a) => println(a)
    case Failure(a) => {
      println("failure")
      println(a)
    }
  }

import shapeless._,contrib.scalaz._
import scalaz._,syntax.validation._

case class Foo(i: Int,s: String)

implicit val fooIso = Iso.hlist(Foo.apply _,Foo.unapply _)

val valHList = sequence(1.successNel[String] :: "2".successNel[String] :: HNil)

scala> valHList.map(fooIso.from)
res0: scalaz.Validation[scalaz.NonEmptyList[String],Foo] = Success(Foo(1,2))