scala – DSL提取案例类字段名称
发布时间:2020-12-16 18:02:00 所属栏目:安全 来源:网络整理
导读:我正在尝试构建一个DSL,但我遇到了一个问题:它适用于案例类,但我想知道提取案例类字段名称的最简单方法.我想到的一个想法是使用宏来丰富我的Case类的类型,但我不愿意. trait QueryDSL[CC] { def meta: CC implicit object StringIsFieldType extends Field[
我正在尝试构建一个DSL,但我遇到了一个问题:它适用于案例类,但我想知道提取案例类字段名称的最简单方法.我想到的一个想法是使用宏来丰富我的Case类的类型,但我不愿意.
trait QueryDSL[CC] { def meta: CC implicit object StringIsFieldType extends Field[CC,String] { def name = "FakeNAME" } implicit def implQuery[V](b: V): Query[CC] = new Query[CC](meta) implicit def implField[V](b: V)(implicit ev: Field[CC,V]): QueryField[CC,V] = new QueryField(ev) } case class Query[CC](meta: CC,clauses: List[Clause[_]] = Nil) { def setProperty[F](clause: CC ? Clause[F]): Query[CC] = copy(clauses = clause(meta) :: clauses) } trait Field[V,M] extends scala.AnyRef { def name: scala.Predef.String } abstract class Clause[V](val fieldName: String,value: V) case class EqClause[V](override val fieldName: String,value: V) extends Clause[V](fieldName,value) class QueryField[CC,M](field: Field[CC,M]) { def eqs(v: M) = EqClause(field.name,v) } /// ################# case class TestingCaseClass(displayName:String = "Bonjour",active:Boolean = false) object Testing extends QueryDSL[TestingCaseClass] { def meta = new TestingCaseClass } import Testing._ val query = Testing setProperty(_.displayName eqs "Hallo") 我想query.clauses等于:List(EqClause(displayName,Hallo)) 解决方法
一些想法
鉴于我正确设法跟踪转换流程.你的最后一行 import Testing._ val query = Testing setProperty(_.displayName eqs "Hallo") 将QueryDSL的含义纳入范围.为了让Testing获取方法setProperty,它将使用implQuery转换为Query.然后displayName,为了获取方法eqs使用implField转换为QueryField,implField本身需要一个类型为Field [TestingCaseClass,String]的隐式值.在范围中确实存在此类型的值:StringIsFieldType.它扩展到 val query = Testing.implQuery[QueryDSL[TestingCaseClass]](Testing).setProperty { (cc : TestingCaseClass) => Testing.implField[String](cc.displayName)(Testing.StringIsFieldType).eqs("Hallo") } 我想你想要的东西 trait Field[CaseClassType,FieldName] { type typeOfThisField } 其中FieldName是单例文字类型String(name)(编译器中的有效类型,但我认为只能使用宏表示). 也许你正在寻找什么 使用无形2.2.5及其singleton-typed-literals的实现: import shapeless._ // Clauses abstract class Clause[V](val fieldName: String,value) // Fields sealed abstract class Field[CC,FieldName] { // The name of the field val fieldName: String // The type of the field type fieldType // How to extract this field def get(cc : CC) : fieldType } object Field { // fieldType is existencial in Field but parametric in Fied.Aux // used to explict constraints on fieldType type Aux[CC,FieldName,fieldType_] = Field[CC,FieldName] { type fieldType = fieldType_ } def apply[CC,fieldType_](fieldWitness : Witness.Lt[String],ext : CC => fieldType_) : Field.Aux[CC,fieldWitness.T,fieldType_] = new Field[CC,fieldWitness.T] { val fieldName : String = fieldWitness.value type fieldType = fieldType_ def get(cc : CC) : fieldType = ext(cc) } } // Queries case class Query[CC](meta: CC,clauses: List[Clause[_]] = Nil) { def setProperty[F](clause: CC ? Clause[F]): Query[CC] = copy(clauses = clause(meta) :: clauses) } class QueryField[CC,M](field: Field.Aux[CC,_,M]) { def eqs(v: M) = EqClause(field.fieldName,v) } trait QueryDSL[CC] { def meta: CC implicit def implQuery[V](b: V): Query[CC] = new Query[CC](meta) implicit def implField[fieldName,V](b: V)(implicit ev: Field.Aux[CC,fieldName,V] = new QueryField(ev) } /// ################# object Example extends App { case class TestingCaseClass(displayName:String = "Bonjour",active:Boolean = false) implicit val displayName = Field(Witness("displayName"),(cc : TestingCaseClass) => cc.displayName) implicit val active = Field(Witness("active"),(cc : TestingCaseClass) => cc.active ) object Testing extends QueryDSL[TestingCaseClass] { def meta = new TestingCaseClass } import Testing._ val queryDisplayName = Testing setProperty(_.displayName eqs "Hallo") println(s"queryDisplayName = $queryDisplayName") val queryActive = Testing setProperty(_.active eqs true) println(s"queryActive = $queryActive") } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |