在Scala中自定义“let”表达式
发布时间:2020-12-16 09:53:23 所属栏目:安全 来源:网络整理
导读:我很乐意让我们构建类似于 Scala中的Haskell中的那个.我尝试了几种方法,但似乎没有一种方法.这是一些代码: object CustomLet extends App { val data = for (i - 1 to 1024; j - 1 to 512) yield (i % j) * i * (i + 1) - 1 def heavyCalc() = { println("h
我很乐意让我们构建类似于
Scala中的Haskell中的那个.我尝试了几种方法,但似乎没有一种方法.这是一些代码:
object CustomLet extends App { val data = for (i <- 1 to 1024; j <- 1 to 512) yield (i % j) * i * (i + 1) - 1 def heavyCalc() = { println("heavyCalc called"); data.sum } def doSomethingWithRes(res: Int) = { println(s"${res * res}") 1 } def cond(value: Int): Boolean = value > 256 // not really usable,even though it's an expression (2x heavyCalc calls) def withoutLet() = if (cond(heavyCalc())) doSomethingWithRes(heavyCalc()) else 0 // not an expression def letWithVal(): Int = { val res = heavyCalc() if (cond(res)) doSomethingWithRes(res) else 0 } // a lot of code to simulate "let",at least it is an expression def letWithMatch(): Int = heavyCalc() match { case res => if (cond(res)) doSomethingWithRes(res) else 0 } // not perfect solution from // https://stackoverflow.com/questions/3241101/with-statement-equivalent-for-scala/3241249#3241249 def let[A,B](param: A)(body: A => B): B = body(param) // not bad,but I'm not sure if it could handle more bindings at once def letWithApp(): Int = let(heavyCalc()) {res => if (cond(res)) doSomethingWithRes(res) else 0} List[(String,() => Int)]( ("withoutLet",withoutLet),("letWithVal",letWithVal),("letWithMatch",letWithMatch),("letWithApp",letWithApp) ).foreach( item => item match { case (title,func) => { println(s"executing $title") val ret = func() println(s"$title finished with $ret") println() } } ) } 这是它的理想外观(只有一个绑定,更多可以分隔,;不确定in关键字): // desired look def letTest(): Int = let res = heavyCalc() in if (cond(res)) doSomethingWithRes(res) else 0 我不确定它是否可能,但我没有大多数高级Scala之类的东西,比如宏,所以我无法分辨. 编辑1:要清楚,我期待的主要内容是:表达和相对简单的语法(如上所述). 解决方法
你可以使用前进管道:
object ForwardPipeContainer { implicit class ForwardPipe[A](val value: A) extends AnyVal { def |>[B](f: A => B): B = f(value) } } 像这样使用: import ForwardPipeContainer._ def f(i: Int) = i * i println( f(3) |> (x => x * x) ) 您可以在元组中放置多个参数: println( (f(2),f(3)) |> (x => x._1 * x._2) ) 如果与部分函数synatx结合使用会更好看: println( (f(2),f(3)) |> { case (x,y) => x * y } ) 这个答案是What is a good way of reusing function result in Scala的变种,两者都是基于Cache an intermediate variable in an one-liner,我得到了最初的想法. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
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