为什么我的Scala列表会在以下代码中消失？

发布时间：2020-12-16 09:09:21 所属栏目：安全来源：网络整理

导读：val files = new File("data").list()val filtered = files.filter(name = name.contains("txn"))val masterList = new ListBuffer[String]for (file - filtered) { val lines = Source.fromFile(new File("data" + file),"UTF-16").getLines val cleaned

val files = new File("data").list()
val filtered = files.filter(name => name.contains("txn"))
val masterList = new ListBuffer[String]
for (file <- filtered) {
  val lines = Source.fromFile(new File("data" + file),"UTF-16").getLines
  val cleaned = lines.filter(!masterList.contains(_))
  println("*" + cleaned.length)
  cleaned.foreach(println(_))
  println("**" + cleaned.length)
  cleaned.foreach(masterList.append(_))
}

代码的输出如下

*175
**0

我不明白为什么我的名单消失了

解决方法

clean是一个迭代器.

scala> val cleaned = lines.filter(_!="")
cleaned: Iterator[String] = non-empty iterator

分配后,它是非空的. scala中的迭代器是单独使用的 – 一旦你遍历它(例如通过应用长度方法)它变为空：

scala> cleaned.length
res0: Int = 13

scala> cleaned.length
res1: Int = 0

您可以通过转换为List或Seq(lazy)来修复该行为：

scala> val lines=Source.fromFile("bla.txt").getLines
lines: Iterator[String] = non-empty iterator

scala> val cleaned = lines.filter(_!="").toSeq
cleaned: Seq[String] = Stream(first,?)

scala> cleaned.length
res4: Int = 13

scala> cleaned.length
res5: Int = 13

（编辑：李大同）

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