scala – 如何手动创建TypeTag？

object X {
  import reflect.runtime.universe._
  def tt[A : TypeTag](a: A) = typeTag[A] // how to do this manually?
  val t = tt(List("")(_))
}

scalac -Xprint：typer< file> .scala导致

package <empty> {
  object X extends scala.AnyRef {
    def <init>(): X.type = {
      X.super.<init>();
      ()
    };
    import scala.reflect.runtime.`package`.universe._;
    def tt[A >: Nothing <: Any](a: A)(implicit evidence$1: reflect.runtime.universe.TypeTag[A]): reflect.runtime.universe.TypeTag[A] = scala.reflect.runtime.`package`.universe.typeTag[A](evidence$1);
    private[this] val t: reflect.runtime.universe.TypeTag[Int => String] = X.this.tt[Int => String](((x$1: Int) => immutable.this.List.apply[String]("").apply(x$1)))({
      val $u: reflect.runtime.universe.type = scala.this.reflect.runtime.`package`.universe;
      val $m: $u.Mirror = scala.this.reflect.runtime.`package`.universe.runtimeMirror(this.getClass().getClassLoader());
      $u.TypeTag.apply[Int => String]($m,{
        final class $typecreator1 extends TypeCreator {
          def <init>(): $typecreator1 = {
            $typecreator1.super.<init>();
            ()
          };
          def apply[U >: Nothing <: scala.reflect.base.Universe with Singleton]($m$untyped: scala.reflect.base.MirrorOf[U]): U#Type = {
            val $u: U = $m$untyped.universe;
            val $m: $u.Mirror = $m$untyped.asInstanceOf[$u.Mirror];
            $u.TypeRef.apply($u.ThisType.apply($m.staticModule("scala").asModuleSymbol.moduleClass),$m.staticClass("scala.Function1"),scala.collection.immutable.List.apply[$u.Type]($m.staticClass("scala.Int").asTypeSymbol.asTypeConstructor,$m.staticClass("java.lang.String").asTypeSymbol.asTypeConstructor))
          }
        };
        new $typecreator1()
      })
    });
    <stable> <accessor> def t: reflect.runtime.universe.TypeTag[Int => String] = X.this.t
  }
}

它似乎完全是编译器魔术,因为类型是硬编码的.不过有没有办法手动执行此操作？