scalar中的基于Ordered和Ordering两种比较器

发布时间：2020-12-16 09:03:39 所属栏目：安全来源：网络整理

导读：1Ordered class PP( var name: String, var age: Int) extends Ordered[PP] { override def compare(that: PP) = if ( this .age that.age) - 1 else if ( this .age that.age) 1 else this .name.compareTo(that.name); override def toString = s " PP($na

1>Ordered

class PP(var name: String,var age: Int) extends Ordered[PP] {
  override def compare(that: PP) = if (this.age > that.age) -1 else if (this.age < that.age) 1 else this.name.compareTo(that.name);

  override def toString = s"PP($name,$age)"
}


mutable.SortedSet(new PP("张三",12),new PP("Ahan1",13),new PP("han1",13)).foreach(print(_))

>Ordering(这里通过需要将写在伴生对象里,必须用参数接收,必须用implicit关键字修饰,也可采用第二种方法写)

class PPA(var name: String,var age: Int) {
  override def toString = s"PPA($name,$age)"
}

object PPA {
  implicit val obj1 = new Ordering[PPA] {
    override def compare(x: PPA,y: PPA): Int = {
      if (x.age < y.age) -1 else 1
    }
  }
}

mutable.SortedSet(new PPA("张三",new PPA("Ahan1",new PPA("han1",13)).foreach(print(_))

第二种方案:(同样在伴生对象里)

object PPA {

  implicit object obj extends Ordering[PPA] {
    override def compare(x: PPA,y: PPA): Int = {
      if (x.age < y.age) -1 else 1
    }
  }

}

（编辑：李大同）

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