scala – 如何通过右边的分隔符拆分字符串？

发布时间：2020-12-16 08:50:39 所属栏目：安全来源：网络整理

导读：如何用右边的分隔符拆分字符串？例如 scala "hello there how are you?".rightSplit(" ",1)res0: Array[java.lang.String] = Array(hello there how are,you?) Python有一个.rsplit()方法,这是我在Scala中所追求的： In [1]: "hello there how are you?".rs

如何用右边的分隔符拆分字符串？

例如

scala> "hello there how are you?".rightSplit(" ",1)
res0: Array[java.lang.String] = Array(hello there how are,you?)

Python有一个.rsplit()方法,这是我在Scala中所追求的：

In [1]: "hello there how are you?".rsplit(" ",1)
Out[1]: ['hello there how are','you?']

解决方法

我认为最简单的解决方案是搜索索引位置,然后根据它进行拆分.例如：

scala> val msg = "hello there how are you?"
msg: String = hello there how are you?

scala> msg splitAt (msg lastIndexOf ' ')
res1: (String,String) = (hello there how are," you?")

因为有人在lastIndexOf上回复了-1,所以解决方案完全没问题：

scala> val msg = "AstringWithoutSpaces"
msg: String = AstringWithoutSpaces

scala> msg splitAt (msg lastIndexOf ' ')
res0: (String,String) = ("",AstringWithoutSpaces)

（编辑：李大同）

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