bash – 如何根据多个嵌入数字对文件路径进行排序？

例如,在目录名params_R_7_C_16_RP_0中,7是参数R的值,16是参数C的值,0是参数RP的值.

我想获取当前目录树中的所有results.txt文件,按其托管目录中的R,C和RP的嵌入值进行排序.

我首先使用以下命令来获取我要解析的results.txt文件：

find ./ -name "results.txt"

输出是：

./params_R_11_C_9_RP_0/results.txt 
./params_R_7_C_9_RP_0/results.txt
./params_R_7_C_4_RP_0/results.txt
./params_R_11_C_16_RP_0/results.txt 
./params_R_9_C_4_RP_0/results.txt
./params_R_5_C_9_RP_0/results.txt 
./params_R_9_C_25_RP_0/results.txt 
./params_R_7_C_16_RP_0/results.txt 
./params_R_5_C_25_RP_0/results.txt 
./params_R_5_C_16_RP_0/results.txt 
./params_R_11_C_4_RP_0/results.txt
./params_R_9_C_16_RP_0/results.txt
./params_R_7_C_25_RP_0/results.txt
./params_R_11_C_25_RP_0/results.txt 
./params_R_5_C_4_RP_0/results.txt 
./params_R_9_C_9_RP_0/results.txt

我尝试了以下排序命令：

find ./ -name "results.txt" | sort

这导致词法排序：

./params_R_11_C_16_RP_0/results.txt
./params_R_11_C_25_RP_0/results.txt
./params_R_11_C_4_RP_0/results.txt
./params_R_11_C_9_RP_0/results.txt
./params_R_5_C_16_RP_0/results.txt
./params_R_5_C_25_RP_0/results.txt
./params_R_5_C_4_RP_0/results.txt
./params_R_5_C_9_RP_0/results.txt
./params_R_7_C_16_RP_0/results.txt
./params_R_7_C_25_RP_0/results.txt
./params_R_7_C_4_RP_0/results.txt
./params_R_7_C_9_RP_0/results.txt
./params_R_9_C_16_RP_0/results.txt
./params_R_9_C_25_RP_0/results.txt
./params_R_9_C_4_RP_0/results.txt
./params_R_9_C_9_RP_0/results.txt

但我真正想要的是选择性数字排序：首先是R值,然后是C,然后是RP：

./params_R_5_C_4_RP_0/results.txt
./params_R_5_C_9_RP_0/results.txt
./params_R_5_C_16_RP_0/results.txt
./params_R_5_C_25_RP_0/results.txt
./params_R_7_C_4_RP_0/results.txt
./params_R_7_C_9_RP_0/results.txt
./params_R_7_C_16_RP_0/results.txt
./params_R_7_C_25_RP_0/results.txt
./params_R_9_C_4_RP_0/results.txt
./params_R_9_C_9_RP_0/results.txt
./params_R_9_C_16_RP_0/results.txt
./params_R_9_C_25_RP_0/results.txt
...

我在生成路径列表时考虑填充嵌入的数字(例如,params_R_005_C_004_RP_0),但这需要额外的处理步骤,我想避免.

可以直接实现所需的分类吗？