bash中的参数太多错误
发布时间:2020-12-16 01:47:54 所属栏目:安全 来源:网络整理
导读:我正在编写一个脚本来删除目录中的所有文件以进行练习.我在我的变量周围使用引号,但我仍然收到以下错误: /usr/local/bin/deleteall: line 6: [: too many arguments/usr/local/bin/deleteall: line 11: [: too many arguments 这是我的代码: #!/bin/bash#D
我正在编写一个脚本来删除目录中的所有文件以进行练习.我在我的变量周围使用引号,但我仍然收到以下错误:
/usr/local/bin/deleteall: line 6: [: too many arguments /usr/local/bin/deleteall: line 11: [: too many arguments 这是我的代码: #!/bin/bash #Deletes all files in the current directory read -p "You are about to delete all files in $(pwd). Are you sure you want to do this? y/n" yn echo $yn if [ [ "$yn" = "y" ] -o [ "$yn" = "Y" ] ] ; then for i in `ls`; do rm $i done exit; elif [ [ "$yn" = "n" ] -o [ "$yn" = "N" ] ] ; then exit; else read -p "Please enter y (yes) or n (no)" exit; fi 这是整个输出: You are about to delete all files in <my dir>. Are you sure you want to do this? y/nn n /usr/local/bin/deleteall: line 6: [: too many arguments /usr/local/bin/deleteall: line 11: [: too many arguments Please enter y (yes) or n (no)n 我究竟做错了什么? 解决方法
这条线似乎有问题:
if [ [ "$yn" = "y" ] -o [ "$yn" = "Y" ] ] ; then 您可以将其替换为: if [[ "$yn" == [yY] ]]; then PS:对于检查n或N的行执行相同的操作. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |