如何一次定义类似的bash函数

发布时间：2020-12-16 01:44:28 所属栏目：安全来源：网络整理

导读：我在?/ .bashrc中有这些函数： function guard() { if [ -e 'Gemfile' ]; then bundle exec guard "$@" else command guard "$@" fi}function rspec() { if [ -e 'Gemfile' ]; then bundle exec rspec "$@" else command rspec "$@" fi}function rake() { if

我在?/ .bashrc中有这些函数：

function guard() {
    if [ -e 'Gemfile' ]; then
    bundle exec guard "$@"
    else
    command guard "$@"
    fi
}
function rspec() {
    if [ -e 'Gemfile' ]; then
    bundle exec rspec "$@"
    else
    command rspec "$@"
    fi
}
function rake() {
    if [ -e 'Gemfile' ]; then
        bundle exec rake "$@"
    else
        command rake "$@"
    fi
}

如您所见,这些功能非常相似.我想一次定义这3个函数.有办法吗？

环境

bash --version
GNU bash,version 3.2.51(1)-release (x86_64-apple-darwin13)

解决方法

$cat t.sh
#!/bin/bash

for func in guard rspec rake; do
        eval "
        ${func}() {
                local foo=(command ${func})
                [ -e 'Gemfile' ] && foo=(bundle exec ${func})
                "${foo[@]}" "$@"
        }
        "
done

type guard rspec rake

$./t.sh
guard is a function
guard ()
{
    local foo=(command guard);
    [ -e 'Gemfile' ] && foo=(bundle exec guard);
    "${foo[@]}" "$@"
}
rspec is a function
rspec ()
{
    local foo=(command rspec);
    [ -e 'Gemfile' ] && foo=(bundle exec rspec);
    "${foo[@]}" "$@"
}
rake is a function
rake ()
{
    local foo=(command rake);
    [ -e 'Gemfile' ] && foo=(bundle exec rake);
    "${foo[@]}" "$@"
}

关于eval的常见警告适用.

（编辑：李大同）

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