Bash“not”：反转命令的退出状态

发布时间：2020-12-16 01:34:14 所属栏目：安全来源：网络整理

导读：我知道我能做到这一点…… if diff -q $f1 $f2then echo "they're the same"else echo "they're different"fi 但是,如果我想否定我正在检查的条件呢？即这样的事情(显然不起作用) if not diff -q $f1 $f2then echo "they're different"else echo "they're th

我知道我能做到这一点……

if diff -q $f1 $f2
then
    echo "they're the same"
else
    echo "they're different"
fi

但是,如果我想否定我正在检查的条件呢？即这样的事情(显然不起作用)

if not diff -q $f1 $f2
then
    echo "they're different"
else
    echo "they're the same"
fi

我可以这样做……

diff -q $f1 $f2
if [[ $? > 0 ]]
then
    echo "they're different"
else
    echo "they're the same"
fi

我在哪里检查前一个命令的退出状态是否大于0.但这感??觉有点尴尬.有没有比较惯用的方法呢？

if ! diff -q $f1 $f2; then ...

（编辑：李大同）

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