用于在bash printf内着色的ANSI转义码

#!/bin/bash

a=foo
b=6
c=a
d="e[33m"  # opening ansi color code for yellow text
e="e[0m"   # ending ansi code
f=$d

printf "1. foon"
printf "2. $an"
printf "3. %sn" "$a"
printf "4. %sn" "${!c}"
printf "5. %${b}sn" "$a"
printf "6. $d%s$en" "$a" # will be yellow
printf "7. $f%s$en" "$a" # will be yellow
printf '8. %s%s%sn' "$d" "$a" "$e" # :(
printf "9. %s%s%sn" "$f" "$a" "$e" # :(

是否可以使用％s扩展颜色变量并查看颜色开关？

输出：

1. foo
2. foo
3. foo
4. foo
5.    foo
6. foo
7. foo
8. e[33mfooe[0m
9. e[33mfooe[0m

注意：6.和7.确实是黄色的

编辑

printf "10. %b%s%bn" "$f" "$a" "$e" # :)

……终于！这是执行它的命令,感谢Josh！