如何用BASH中的递增数替换所有匹配?
发布时间:2020-12-16 01:17:20 所属栏目:安全 来源:网络整理
导读:我有这样的文本文件: AAAAAA this is some content.This is AAAAAA some more content AAAAAA. AAAAAAThis is yet AAAAAA some more [AAAAAA] content. 我需要用递增的数字替换所有出现的AAAAAA,例如,输出看起来像这样: 1 this is some content.This is 2
我有这样的文本文件:
AAAAAA this is some content. This is AAAAAA some more content AAAAAA. AAAAAA This is yet AAAAAA some more [AAAAAA] content. 我需要用递增的数字替换所有出现的AAAAAA,例如,输出看起来像这样: 1 this is some content. This is 2 some more content 3. 4 This is yet 5 some more [6] content. 如何用递增的数字替换所有匹配?
这是一种方法:
$awk '{for(x=1;x<=NF;x++)if($x~/AAAAAA/){sub(/AAAAAA/,++i)}}1' file 1 this is some content. This is 2 some more content 3. 4 This is yet 5 some more [6] content. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |