bash – unix命令从单词的第一个和最后一个出现之间获取行并写入

1)获取第一个和最后一个匹配的行号.

2)打印这些范围之间的行范围.

$read first last <<< $(grep -n stackoverflow your_file | awk -F: 'NR==1 {printf "%d ",$1}; END{print $1}')
$awk -v f=$first -v l=$last 'NR>=f && NR<=l' your_file

说明

> read first last读取两个值并将它们存储在$first和$last中.
> grep -n stackoverflow your_file greps并显示如下输出：number_of_line：output
> awk -F：’NR == 1 {printf“％d”,$1}; END {print $1}’)打印文件中stackoverflow的第一个和最后一个匹配的行数.

和

> awk -v f = $first -v l = $last’NR> = f&& NR< = l'your_file打印从$first行号到$last行号的所有行.
测试

$cat a
here we
have some text
stackoverflow

and other things
bla
bla
bla bla
stackoverflow
and whatever else
stackoverflow
to make more fun
blablabla

$read first last <<< $(grep -n stackoverflow a | awk -F: 'NR==1 {printf "%d ",$1}; END{print $1}')
$awk -v f=$first -v l=$last 'NR>=f && NR<=l' a
stackoverflow

and other things
bla
bla
bla bla
stackoverflow
and whatever else
stackoverflow

按步骤：

$grep -n stackoverflow a
3:stackoverflow
9:stackoverflow
11:stackoverflow

$grep -n stackoverflow a | awk -F: 'NR==1 {printf "%d ",$1}; END{print $1}'
3 11

$read first last <<< $(grep -n stackoverflow a | awk -F: 'NR==1 {printf "%d ",$1}; END{print $1}')

$echo "first=$first,last=$last"
first=3,last=11