这个其他版本的bash fork炸弹是如何工作的？

:(){ :|:& };:

bash fork炸弹的工作原理.

但是,我见过另一个版本(特别是针对bash)

#!/bin/bash
$0 &
$0 &

在上面提到的原始叉炸弹问题的Wikipedia fork bomb article和SO answer到closed duplicate.

我正在寻找解释第二种(可能不常见的)叉式炸弹的工作方式.我已经用我目前对其作用的理解来评论下面的代码,但是我并没有真正了解它如何以其他版本的bash fork炸弹的方式实现无限递归(可能是由于我对bash的理解不足)流程和背景).

#!/bin/bash    # Specifies the location of the executable
               # to use in executing this script.
$0 &           # Duplicates (executes a new instance
               # of) the current running process ('$0')
               # (which would be the invocation of bash used
               # to start running the script,right?)
               # and background it ('&').
$0 &           # Do the same as above,where $0 would be
               # equivalent to the initial call to bash
               # used to start the script,right? Or,would
               # it be the backgrounded call to bash from the
               # second line? I'm leaning towards the former.

编辑：我对脚本的修改理解(至少在目前我担心的抽象层次上)以评论代码的形式出现.我已经将我原来的评论代码留给了未来的观众,他们可能会遇到我最初的误解.假设脚本存在于bomb.sh中.

#!/bin/bash    # Script will execute using /bin/bash executable.
$0 &           # The current process (P) will spawn a child process (C1)
               # by invoking the command that spawned P
               # (/bin/bash ./bomb.sh). This makes the script recursive.
               # & allows processes to run in the background
               # (allowing process death and avoiding a potential
               # process limit).
$0 &           # Process P spawns a second child process (C2),also 
               # in the background,which gives us the exponential growth
               # (in base 2) that we want per level of recursion.