bash脚本中$@和$*的区别

参见英文答案 > Parsing/passing command line arguments to a bash script – what is the difference between “$@” and “$*”?????????????????????????????????????3个
我是bash的新手,我正在学习它,我怀疑使用$@和S *之间的真正区别.

我在这里红了Bash Special Parameters

我知道两者都扩展到位置参数,但差异发生在双引号内.
顺便说一句,“$@”=“$1”“$2”…“$n”可能与“S *”=“$1 $2 … $n”不同.

我尝试用一??个简单的脚本来理解它：

if [ $# -gt 0 ]; then
       echo "Your command line contains $# arguments" 
else
       echo "Your command line contains no arguments"
       exit  fi

echo "Params are: "
echo $@  
echo $* 
echo "$@"    
echo "$*"

如果我在终端中执行我的脚本~~ / my_script par1 par2 par3

结果总是一样的：

Params are:
par1 par2 par3
par1 par2 par3
par1 par2 par3
par1 par2 par3

也许我不明白这两个特殊变量的实际用途以及我的例子是否正确.我想用一个很好的例子来弄清楚这一点.

echo "Params for: $@"
for item in "${@}"
do
        echo $item --
done

echo "Params for : $*"
for item in "${*}"
do
        echo $item --
done

$./a par1 par2 par3
Your command line contains 3 arguments
Params for: $@
par1 --
par2 --
par3 --
Params for : $*
par1 par2 par3 --