regex – bash控制语句//,/ double forward slash

发布时间：2020-12-15 21:24:24 所属栏目：安全来源：网络整理

导读：在这个例子中//,/是什么意思？ for SCHEMA_ONLY_DB in ${SCHEMA_ONLY_LIST//,/}do SCHEMA_ONLY_CLAUSE="$SCHEMA_ONLY_CLAUSE or datname ~ '$SCHEMA_ONLY_DB'"doneSCHEMA_ONLY_LIST="mydb1,mydb2,mydb3,mydb4"SCHEMA_ONLY_DB=mydb1 $SCHEMA_ONLY_CLAUSE现已

在这个例子中//,/是什么意思？

for SCHEMA_ONLY_DB in ${SCHEMA_ONLY_LIST//,/}
do
    SCHEMA_ONLY_CLAUSE="$SCHEMA_ONLY_CLAUSE or datname ~ '$SCHEMA_ONLY_DB'"
done

SCHEMA_ONLY_LIST="mydb1,mydb2,mydb3,mydb4"
SCHEMA_ONLY_DB=mydb1

$SCHEMA_ONLY_CLAUSE现已填充：

echo $SCHEMA_ONLY_CLAUSE
or datname ~ 'mydb1' or datname ~ 'mydb2' or datname ~ 'mydb3'

解决方法

从bash(1)手册页( http://linux.die.net/man/1/bash)：

${parameter/pattern/string}

Pattern substitution. The pattern is expanded to produce a pattern just as in pathname expansion. Parameter is expanded and the longest match of pattern against its value is replaced with string. If pattern begins with /,all matches of pattern are replaced with string. Normally only the first match is replaced. If pattern begins with #,it must match at the beginning of the expanded value of parameter. If pattern begins with %,it must match at the end of the expanded value of parameter. If string is null,matches of pattern are deleted and the / following pattern may be omitted. If parameter is @ or *,the substitution operation is applied to each positional parameter in turn,and the expansion is the resultant list. If parameter is an array variable subscripted with @ or *,the substitution operation is applied to each member of the array in turn,and the expansion is the resultant list.

也就是说,${something //,/}被扩展为$something,其中包含所有出现的内容,已删除.

（编辑：李大同）

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