从另一个脚本调用一个Bash脚本,并使用引号和空格传递它的参数
发布时间:2020-12-15 20:01:58 所属栏目:安全 来源:网络整理
导读:我在Linux上做了两个测试bash脚本,使问题清晰。 TestScript1看起来像: echo "TestScript1 Arguments:" echo "$1" echo "$2" echo "$#" ./testscript2 $1 $2 TestScript2看起来像: echo "TestScript2 Arguments received from TestScript1:" echo "$1" ech
我在Linux上做了两个测试bash脚本,使问题清晰。
TestScript1看起来像: echo "TestScript1 Arguments:" echo "$1" echo "$2" echo "$#" ./testscript2 $1 $2 TestScript2看起来像: echo "TestScript2 Arguments received from TestScript1:" echo "$1" echo "$2" echo "$#" 当我以下列方式执行testscript1: ./testscript1 "Firstname Lastname" testmail@domain.com 所需的输出应为: TestScript1 Arguments: Firstname Lastname testmail@domain.com 2 TestScript2 Arguments received from TestScript1: Firstname Lastname testmail@domain.com 2 但实际输出是: TestScript1 Arguments: Firstname Lastname testmail@domain.com 2 TestScript2 Arguments received from TestScript1: Firstname Lastname 3 我如何解决这个问题?我想得到所需的输出,而不是实际的输出。
在Testscript中引用你的参数1:
echo "TestScript1 Arguments:" echo "$1" echo "$2" echo "$#" ./testscript2 "$1" "$2" (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |