当匹配发现时,shell – sed替换整行

sed 's/.*six.*/fault/' file     # check all lines
sed '/six/s/.*/fault/' file     # matched lines -> then remove

它获得包含六个的全部行，并将其替换为故障。

例：

$ cat file
six
asdf
one two six
one isix
boo
$ sed 's/.*six.*/fault/'  file
fault
asdf
fault
fault
boo

它基于this solution至Replace whole line containing a string using Sed

更一般地说，您可以使用表达式sed’/match/s/.*/replacement/’文件。这将在包含匹配的行中执行sed / s / match / replacement /’表达式。在你的情况下，这将是：

sed '/six/s/.*/fault/' file

What if we have ‘one two six eight eleven three four’ and we want to
include ‘eight’ and ‘eleven’ as our “bad” words?

在这种情况下，我们可以在多个条件下使用-e：

sed -e 's/.*six.*/fault/' -e 's/.*eight.*/fault/' file

等等。

还是：

sed '/eight/s/.*/XXXXX/; /eleven/s/.*/XXXX/' file